E lost the maximum number of matches.
2nd Highest is either B or H so cant determine.
option (a) is correct
From solution of previous question maximum points scored by lowest scoreris 11
In this case top 3 players should get maximum possible points and remaining 5 should get equal points and Rajesh got advanced with tie breaker rule.
Bottom 5 player have in total 4 x 5 = 20 matches and each match will fetch minimum possible points when its result is tie. So minimum points in 20 matches is 20 x 2 = 40 when distributed equally to bottom 5 each of them will get 40/5 = 8 points.
If a player eliminated in 1st stage even after scoring maximum possible point the it is possible when top 5 has same points and Rajesh got eliminated with tie breaker rule. In this case bottom three got points because of matches between them.
Out of 56 matches there are 6 matches played among bottom three hence total points in remaining 56 - 6 = 50 matches is 50 x 3 = 150 that is equally divided among top 5 players equally i.e 30 points each, So Rajesh can not get advanced even after getting 30 points.
A lost both the matches to B or H not B and H hence option C is incorrect.
If G played with B in semifinal round then H lost both the matches against B in the stage 1
Number of matches in stage 1 is 2(7 x 8/2) = 56, at semifinal stage we have 3 matches (2 semifinal and 1 match for 3rd place) and 1 final match, hence total number of matches is 56 + 3 + 1 = 60
Seed 9 will play with seed, 1, 3, 5, 7, 11, 13, and 15 without an upset seed 9 can with seed 11, 13, and 15, for minimum number of upset let seed 1 won all the matches and seed 9 won against seed 3 and 5, in that case number of wins of seed 3 and 9 is 5 but with tie breaker rule seed 9 will advance to the next stage.
Total number of matches is 60 and out of those more than 45 matches are upset. But seed 1 need only 9 matches to win the tournament hence seed 1 may win the tournament.
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