If result of stage 2 is interchanged i.e winner becomes looser and vice versa then who won the maximum points in the tournament?

Total number of matches is 21 when divided in 3 stages we will get 7 matches in one stage.
From the given table Ahaskar, Faisal and Gaurav won 4 matches then Dripto won only 2 matches.

In stage I, in a group in total 6 matches and that will have 12 points in total.
Total number of matches in this stage is 4 × 6 = 24
In stage II, total 8 players and they play each other except a player who comes from same group but point of their match in stage I is carried forward hence in stage II total points is 28 × 2 = 56.
Number of matches in stage II is 7 × ( 8/2 ) ? 4 = 24
Total number of matches are as follows:
Stage I : 24
Stage II : 24
And required ratio is 1 : 1.

In stage I, in a group in total 6 matches and that will have 12 points in total.
Total number of matches in this stage is 4 × 6 = 24
In stage II, total 8 players and they play each other except a player who comes from same group but point of their match in stage I is carried forward hence in stage II total points is 28 × 2 = 56.
Number of matches in stage II is 7 × ( 8/2 ) ? 4 = 24
Total number of matches are as follows
Stage I: 24
Stage II: 24
Semifinal: 2
For 3rd place (Looser of semi final): 1
Final: 1
Total number of matches is 52 and hence total number of points is 52 × 2 = 104

In stage I, in a group in total 6 matches and that will have 12 points in total.
Total number of matches in this stage is 4 × 6 = 24
In stage II, total 8 players and they play each other except a player who comes from same group but point of their match in stage I is carried forward hence in stage II total points is 28 × 2 = 56.
Number of matches in stage II is 7 × ( 8/2 ) ? 4 = 24
In stage 1 a player has to win minimum 1 match to advance to the next stage.
Now consider the different groups,
South Kolkata : 1, 8, 9, 16 [seed 9 can advance after beating seed 16 without an upset]
North Kolkata : 2, 7, 10, 15 [seed 10 can advance after beating seed 15 without an upset]
Central Kolkata : 3, 6, 11, 14 [seed 11 can advance after beating seed 14 without an upset]
Saltlake : 4, 5, 12,13 [seed 12 can advance after beating seed 113 without an upset] So seed 12 is the lowest seed who can advance to stage II without causing Upset in stage I, and can win the tournament [Please note here that in stage II or semifinal there may be an Upset

In stage I, in a group in total 6 matches and that will have 12 points in total.
Total number of matches in this stage is 4 × 6 = 24
In stage II, total 8 players and they play each other except a player who comes from same group but point of their match in stage I is carried forward hence in stage II total points is 28 × 2 = 56.
Number of matches in stage II is 7 × ( 8/2 ) ? 4 = 24
In this case we have to minimize the points scored by 4th ranker (Who advanced to Semi Final). In order to minimize the points scored by Ricky Singh top three players should get maximum points, Let points achieved by top three player at the end of stage II is 14, 12 and 10 summing up to 14 + 12 + 10 = 36 and remaining points 56 - 36 = 20 got distributed to bottom 5 players.
To minimize the points scored by Ricky Singh, all of the bottom five got same point (20/5 = 4 points) and with complex tie breaker Ricky is advanced to Semifinal.

For minimum number of matches lets take example of R4 he won 0 matches in stage 1 and 5 matches in stage II. So required minimum number is 5.

from table option (c) is correct.

From the table any option can satisfy the given condition.

No player can win 3 matches

Minimum is 6 and maximum is 10 represented by option