If Ricky Singh a lucky player from South Kolkata reached semi final stage after getting the minimum possible points, then what is the point scored by Mr. Ricky Singh.

In stage I, in a group in total 6 matches and that will have 12 points in total.
Total number of matches in this stage is 4 × 6 = 24
In stage II, total 8 players and they play each other except a player who comes from same group but point of their match in stage I is carried forward hence in stage II total points is 28 × 2 = 56.
Number of matches in stage II is 7 × ( 8/2 ) ? 4 = 24
In stage 2 total points are 56.
Consider bottom 3 players, they must play three matches among themselves and hence they have minimum 6 points with them,
Remaining points 56 - 6 = 50 if equally divided between top 5 then one would get 10 points, so to guarantee a seat in semifinal Ricky Singh has to score 12 points .

From the given information we can complete the following table it is clear that if a team wins 5 games, then also there is no guarantee of its advancement to the next stage, since only 4 teams can go to the next stage.
Note: In the table W ? Wins, L ? Loose, × ? No match (as example there can not be match between 1& and 1, 2 and 2 and so on)
The above is one of such combination. Since after winning 5 matches too, there is no guarantee to advancement, so the answer must be 6, because no two teams can get 7 points each.

First Stage: There is two groups of 8 teams each. In each group, each team plays with every other team and hence total number of matches are ⁸c₂ = 8 × ( 7/2 ) = 28 matches So, in both the groups the total number of matches played at the first stage are 28. And hence 56 matches are played in 1^st stage
Second Stage: In this stage there are 8 teams playing in such a way that in one round 4 teams play with 4 other teams. 4 teams win and go to the next round. That is called knock out tournament.
In the 1^st round no of matches ( 8/2 ) = 4,
In the 2^nd round no of matches = ( 4/2 ) = 2,
In the third or the last round number of match = ( 2/2 ) = 1,
So , total no. of matches in 2^nd stage is 4 + 2 + 1 = 7
Hence total match in the tournament = 56 + 7 = 63

From the given conditions we can form the table as follows:
From the table we can conclude that Karnataka and Punjab have 1 match to play against each other. It is also given that A win can fetch 2 points, and a loss, 0 point.
The maximum points that Gujrat (with lowest point) = 18 + ( 5 × 2 ) = 28 and he may not be eliminated, Similarly there are certain conditions exist where every team has a chance to survive.

2 teams won 2 matches each

In stage I, in a group in total 6 matches and that will have 12 points in total.
Total number of matches in this stage is 4 × 6 = 24
In stage II, total 8 players and they play each other except a player who comes from same group but point of their match in stage I is carried forward hence in stage II total points is 28 × 2 = 56.
Number of matches in stage II is 7 × ( 8/2 ) ? 4 = 24
In stage 1 a player has to win minimum 1 match to advance to the next stage.
Now consider the different groups,
South Kolkata : 1, 8, 9, 16 [seed 9 can advance after beating seed 16 without an upset]
North Kolkata : 2, 7, 10, 15 [seed 10 can advance after beating seed 15 without an upset]
Central Kolkata : 3, 6, 11, 14 [seed 11 can advance after beating seed 14 without an upset]
Saltlake : 4, 5, 12,13 [seed 12 can advance after beating seed 113 without an upset] So seed 12 is the lowest seed who can advance to stage II without causing Upset in stage I, and can win the tournament [Please note here that in stage II or semifinal there may be an Upset

In stage I, in a group in total 6 matches and that will have 12 points in total.
Total number of matches in this stage is 4 × 6 = 24
In stage II, total 8 players and they play each other except a player who comes from same group but point of their match in stage I is carried forward hence in stage II total points is 28 × 2 = 56.
Number of matches in stage II is 7 × ( 8/2 ) ? 4 = 24
Total number of matches are as follows
Stage I: 24
Stage II: 24
Semifinal: 2
For 3rd place (Looser of semi final): 1
Final: 1
Total number of matches is 52 and hence total number of points is 52 × 2 = 104

In stage I, in a group in total 6 matches and that will have 12 points in total.
Total number of matches in this stage is 4 × 6 = 24
In stage II, total 8 players and they play each other except a player who comes from same group but point of their match in stage I is carried forward hence in stage II total points is 28 × 2 = 56.
Number of matches in stage II is 7 × ( 8/2 ) ? 4 = 24
Total number of matches are as follows:
Stage I : 24
Stage II : 24
And required ratio is 1 : 1.

Total number of matches is 21 when divided in 3 stages we will get 7 matches in one stage.
From the given table Ahaskar, Faisal and Gaurav won 4 matches then Dripto won only 2 matches.

Total number of matches is 21 when divided in 3 stages we will get 7 matches in one stage.Hence , required answer is Bhanu.
The new result will be as follows :