How many teams won 4 matches?

C and E won 2 matches.

From the table E won against C and G

From the table G lost 4 matches.

From the table F won 4 matches.

From the solution of previous question we have seen that seed 32 can win the tournament without causing an upset by him. So seed 15 can also win the tournament without causing an upset by him.

From the given conditions we can form the table as follows:
From the table we can conclude that Karnataka and Punjab have 1 match to play against each other. It is also given that A win can fetch 2 points, and a loss, 0 point.
The maximum points that Gujrat (with lowest point) = 18 + ( 5 × 2 ) = 28 and he may not be eliminated, Similarly there are certain conditions exist where every team has a chance to survive.

First Stage: There is two groups of 8 teams each. In each group, each team plays with every other team and hence total number of matches are ⁸c₂ = 8 × ( 7/2 ) = 28 matches So, in both the groups the total number of matches played at the first stage are 28. And hence 56 matches are played in 1^st stage
Second Stage: In this stage there are 8 teams playing in such a way that in one round 4 teams play with 4 other teams. 4 teams win and go to the next round. That is called knock out tournament.
In the 1^st round no of matches ( 8/2 ) = 4,
In the 2^nd round no of matches = ( 4/2 ) = 2,
In the third or the last round number of match = ( 2/2 ) = 1,
So , total no. of matches in 2^nd stage is 4 + 2 + 1 = 7
Hence total match in the tournament = 56 + 7 = 63

From the given information we can complete the following table it is clear that if a team wins 5 games, then also there is no guarantee of its advancement to the next stage, since only 4 teams can go to the next stage.
Note: In the table W ? Wins, L ? Loose, × ? No match (as example there can not be match between 1& and 1, 2 and 2 and so on)
The above is one of such combination. Since after winning 5 matches too, there is no guarantee to advancement, so the answer must be 6, because no two teams can get 7 points each.

In stage I, in a group in total 6 matches and that will have 12 points in total.
Total number of matches in this stage is 4 × 6 = 24
In stage II, total 8 players and they play each other except a player who comes from same group but point of their match in stage I is carried forward hence in stage II total points is 28 × 2 = 56.
Number of matches in stage II is 7 × ( 8/2 ) ? 4 = 24
In stage 2 total points are 56.
Consider bottom 3 players, they must play three matches among themselves and hence they have minimum 6 points with them,
Remaining points 56 - 6 = 50 if equally divided between top 5 then one would get 10 points, so to guarantee a seat in semifinal Ricky Singh has to score 12 points .

In stage I, in a group in total 6 matches and that will have 12 points in total.
Total number of matches in this stage is 4 × 6 = 24
In stage II, total 8 players and they play each other except a player who comes from same group but point of their match in stage I is carried forward hence in stage II total points is 28 × 2 = 56.
Number of matches in stage II is 7 × ( 8/2 ) ? 4 = 24
In this case we have to minimize the points scored by 4th ranker (Who advanced to Semi Final). In order to minimize the points scored by Ricky Singh top three players should get maximum points, Let points achieved by top three player at the end of stage II is 14, 12 and 10 summing up to 14 + 12 + 10 = 36 and remaining points 56 - 36 = 20 got distributed to bottom 5 players.
To minimize the points scored by Ricky Singh, all of the bottom five got same point (20/5 = 4 points) and with complex tie breaker Ricky is advanced to Semifinal.