Draw a table with Student, Standard and Subject.
A's favorite subject is Marathi.
D likes Chemistry and studies in Std VIII with only H.
F likes Physics.
The one who studies in Std VIII likes English.
B does not study in Std VII.
C does not like Geography.
G does not like Biology.
E and A study in the same Std but not with B.
C and F study in the same Std.
Those who study in Std VI do not like mathematics or Biology.
Based on the above information, the classification of the group is as follow in the table.
From option (c),
8 * 8 * 1 * 7 = 8
? 8 ÷ 8 x 1 + 7 = 8
? 8 = 8
Statements
P < Q = R ? S ? T
Conclusions
I. T ? Q (true)
II. R > P (true)
Hence, both conclusions are definitely true.
If we interchanges signs '+' and '÷', then the equation changes into
15 + 9 x 3 - 74 ÷ 2 = 15 + 27 - 37 = 5
Solve all option one by one,
36 + 6 - 3 x 2 = 20
After changing the symbol as per question,
36 ÷ 6 x 3 + 2 = 20
Apply the BODMAS rule,
? 6 x 3 + 2 = 20
? 18 + 2 = 20
? 20 = 20
H ? W ..(i) W < N ...(ii) R = N ...(iii)
Combining these we get H ? W < N = R
Hence R > W and I follows
Again N > W and II follows
And, H < R III follows
4 x 3 x 4 = 48
D ? N ...(i) R = F ...(ii) F > T ...(ii)
From (i) and (ii) D ? R = F or D ? F or F ? D.
Hence either I (F = D ) or II (F > D) follows
From (ii) and (iii) R = F > T or R > T or T < R.
Hence III follows.
M < T ... (i) T > K ...(ii) K = D ...(iii)
From (ii) and (iii) T > K = D or D < T.
Hence I follow
From (i) and (ii) K and M can't be compared
Hence II does not follow
N < O ? R > T; R < A; B ? T
Check for I:
N < O ? R > T
? No definite relation can be found between N and A.
Check for II:
Apply all option one by one.
? 6 x 4 + 2 = 16 ? 4 + 6 x 2 = 16 ? 4 + 12 = 16
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