Last day of century can be Friday, Wednesday, Monday, or Sunday and it repeats the cycle. So 1st day of next century must be either Saturday, Thursday, Tuesday, or Monday and so it must not be Wednesday, friday & Sunday
? = 5103 x 121/100
= 61.74.63 = 6000
S.I. on Rs. 240 for half the time = Rs. 10.
T.D. on Rs. 250 = Rs. 10.
∴ T.D. on Rs. 260 = Rs. | ❨ | 10 | x 260 | ❩ | = Rs. 10.40 |
250 |
The circumcentre of a triangle is always the point of intersection of the Bisectors .Hence required answer will be bisectors .
∴ S.I. on Rs. 450 = Rs. 90.
S.I. on Rs. 540 = Rs. | ❨ | 90 | x 540 | ❩ | = Rs. 108. |
450 |
∴ B.D. = Rs. 108.
So, after 63 days, it will be Monday.
∴ After 61 days, it will be Saturday.
Rate of Interest = 12% per annum
Simple Interest =Rs 6000 per annum
Let 'P' is the principal
SI= (P x R x T)/100
where , SI= Simple Interest
T= Time
R= Rate
? 6000=(P x 1 x 12)/100
? P =(6000 x 100)/12
= Rs 50000
Hence the required amount is Rs 50000
Then, AB + BC = 2x metres.
AC = √2x = (1.41x) m.
Saving on 2x metres = (0.59x) m.
Saving % = | ❨ | 0.59x | x 100 | ❩% | = 30% (approx.) |
2x |
Let 'x' be the required number
0.75x + 75 =x
? 0.25x=75
? x=75 / 0.25 =300
A : B = 2 : 3 and B : C = 5 : 8 = | ❨ | 5 x | 3 | ❩ | : | ❨ | 8 x | 3 | ❩ | = 3 : | 24 |
5 | 5 | 5 |
⟹ A : B : C = 2 : 3 : | 24 | = 10 : 15 : 24 |
5 |
⟹ B = | ❨ | 98 x | 15 | ❩ | = 30. |
49 |
Let the number be y.
Then, 35% of y = 112
( 35 / 100 )y = 112
y = ( 112 x 100 ) / 35
= 320
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