Lets find out 1st April from Zeller's Formula:
f = k + [13 x m - 1 / 5] + D + [D/4] + [C/4] - 2 x C.
In this case k = 1 (since 1st April)
Month m = 2 (As march = 1, April = 2)
D is the last two digit of year here D = 01 (As year is 2001)
C is 1st two digit of century here C = 20 (As year is 2001)
f = 1 + [13 x 2 - 1 / 5] + 01 +[01/4] + [20/4] -2 x 20
f = 1 + [25/5] + 01 + [0.5] + [5] - 40.
f = 1 + 5 + 01 + 0 + 5 - 40 = -28
This - ve value of f can be made positive by adding multiple of 7
So f = - 28 + 28 = 0
So number of odd days is 0,
So 1st April 2001 is Sunday,
So 1st Friday is on 6th April , so next Fridays is 13th, 20th, 27th April.
Let the amount of juice and water in original mixture '4x' litre and '3x' litre respectively.
According to given data,
4x/3x+6 =8/7
28x=24x+48
28x?24x=48
4x = 48
x = 12
Amount of juice = 4x = 4×12 = 48 litre.
Ratio of milk andwater = 4:1
Quantity of water = 35/5 = 7 litres
Quantity of milk = 35 X 4/5 = 28 litres
If 7 litre of water is added, new quantity of water = 14 litre
New ratio of milk and water = 28:14 = 2:1
Let the number be N
According to the question
N - 3N/4 = 163
? N/4 = 163
? N = 652
Let initial quantity be Q, and final quantity be F
F = Q(1 - 8/Q)
=> Q = 20
2|64009( 253 |4 |---------- 45|240 |225 |---------- 503| 1509 | 1509 |---------- | X |----------∴ √64009 = 253.
So, the required number is -128.
? = 6.39 x 128.948 + 5.215 ÷ 12.189 + 25.056
= 639 x 128.948 + 5.215 x (1/12.189) + 25.056
= 823.97772 + 0.427844778 + 25.056
= 849.4615648 ? 852
By the formula, speed= Distance/ Time
= (240 + 240)/27 x (18/5)
= 480/27 x 18/5 = 64 km/h
1 / .003718 = 10000 / 3.718
= 10000 x ( 1/3.718)
= 10000 x .2689
= 2689.
Efficiency of A = 4.16%
Efficiency of B = 1.6 x 4.16 = 6.66%
? Number of days required by B = 100/6.66 = 15 days
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.