The Republic day of India was celebrated on Friday in year 2008. On which day, it will be celebrated in 2012?

Time from 5 am of a particular day to 10 pm on the 4th day is 89 h. Now, the clock loses 16 min in 24 h or on other words, we can say that 23 h 44 min of this clock is equal to 24 h of the correct clock. or (23 + 44/60)
? 356 h of this clock = 24 h of the correct clock
? 89 h of this clock
= (24 x 15/356 x 89) h of correct clock
= 90 h of the correct clock

At 3 O'clock, then minute hand is 15 min away from the hour hand. To coincide, it must gain 15 min as 55 min are gained in 60 min.
15 min are gained in (60/55) x 15 min = 16⁴/₁₁ min
Hence, the hands are coincide at 16⁴/₁₁ min past 3.

Mohan was born on 31st July, August 15 falls on Monday.

18th February, 1997 is Tuesday. So, 17th February, 1998 will also be Tuesday.
Again 16th February, 1999 will also be Tuesday.
Hence, 18th February, 1999 will be Thursday.

26 January, 1996 to 15 August, 2000 days were = 1663
1663 having odd day = 4
? In the year 2000, Independence day will on Tuesday.

The year 2004 is a leap year. It has 2 odd days. The day on 8th February, 2004 is 2 days before the day on 8th February, 2005.
Hence, this day is Sunday

2nd July, 1984 means (1983 years 6 months and 2 days) 1900 years have 1 odd day 83 years have 20 leap years and 63 ordinary years
= (40 + 63) odd days
= 103
= 5 odd days
6 months and 2 days
Jan 31
Feb 29
Mar 31
Apr 30
May 31
June 30
July 02
= 184 days = 2 odd days
Total number of days = (1 + 5 + 2)
= 8 odd days
= 1 odd day
Hence, it was Monday on 2nd July,1984.

The year 1990 has 356 days, i.e., 1 odd day, year 1991 has 356 days, v 1 odd day, year 1992 has 366 days, i.e., 2 odd days. Likewise year 1993, 1994, 1995 have 1 odd days, so calculated from years 1990-95 = (1 + 1 + 2 + 1 + 1 + 1)
= 7 odd days
= 0 odd day
Hence, the year 1996 will have the same calendar as that of the year 1990.

Here, 27th March 1995 was Monday. Now for calculating total number of odd days. First, we calculate total number of days till 1 Number 1994
? Number of days in March 1995 = 27
Number of days in February 1995 = 28
Number of days in January 1995 = 31
Number of days in December 1994 = 31
Number of days in November 1994 = 29/146
? Number of odd days = 146/7 = 20⁶/₇
So, 6 odd days.
? On November 1, 1994 = Monday - 6
= Tuesday

Total number of odd days from December 17, 1899 to December 22, 1901
14 + 356 + 356 = 735
or, 735/7 = 105
= 0 odd days
it was Saturday on December 17, 1899.
So, it will be Saturday on December 22, 1901.