Same as previous question Option A is correct.
At 11 : 50 A.M. from the formula here P = 11 and Q = 50 so required angle is 11 x 50/2 - 30 x 11 = 275 - 330 = -55 or ignoring the negative sign the required angle is 55°
Number of odd days between 6th march 2002 to 6th march 2003 is 1
Number of odd days between 6th march 2003 to 6th march 2004 is 2
Number of odd days between 6th march 2004 to 6th march 2005 is 1
Hence total Number of odd days between 6th march 2002 to 6th march 2005 is 1 + 2 + 1 = 4 odd days so 6th march 2002 is 4 days before Sunday i.e. Wednesday.
When 69 is divided by 7 we will get remainder 6 so the day will be 6 days more than Sunday i.e Saturday.
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 +2 + 1) = 5 days.
? On 31st December, 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
The century divisible by 400 is a leap year. 2100 is not divisible by 400 hence is not a leap year so 2100 is not a leap year, out of remaining 1128 is divisible by 4, so 1128 is a leap year.
39°
At 2 PM angle between minute hand and hour hand is 60° and that at 6 PM is 180° hence percentage change is 200%.
From the formula the required angle is 187.5°
9 :164/11
Consider exactly at 8 : 00, minute hand is at position '12' and hour hand is at '8' hence angle between these two hands at 8 : 00 is 240°.
Case (i) when minute hand is behind Hour hand then required time is (240 - 90)/(11/2) = 150/(11/2) = 300/11 = 27 3/11 minute
Case (ii) when minute hand is ahead of four hand then required time is (240 + 90)/(11/2) = 330/(11/2)
= 330 x 2/11 = 60 minute i.e., at 9 : 00 PM
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