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- Question
- Amit was born 5 years before Rakesh, Rakesh is 3 years younger to Anil. If Amit is now 17 years old, how old is Anil?
Options- A. 8 years
- B. 12 years
- C. 15 years
- D. 19 years
- Correct Answer
- 15 years
ExplanationThe present age of Amit = 17 years
5 years before , age of Rakesh = The present age of Amit - 5 years = 17 ? 5 = 12 years
? Age of Anil = age of Rakesh + 3 years = 12 + 3 = 15 years - 1. Neela is now 3 times as old as her daughter Leela. Ten years back, Neela was 5 times as old as Leela. The age of Leela is
Options- A. 15
- B. 25
- C. 30
- D. 20 Discuss
- 2. Mother was three times the age of her daughter 5 years ago. After 5 years, mother will be twice as old as her daughter. How old is the daughter today?
Options- A. 5 years
- B. 10 years
- C. 15 years
- D. 20 years Discuss
- 3. 2 years ago a mother was 4 times as old as her son. 6 years from now her age will become more than double her son's age by 10 years. What is the present ratio of their ages?
Options- A. 2 : 1
- B. 38 : 11
- C. 19 : 7
- D. 3 : 1 Discuss
- 4. The age of a father is twice that of his son's at present age. After 5 years the sum of their ages will be 85. How old are they now?
Options- A. 40, 20
- B. 46, 23
- C. 60, 30
- D. 50, 25 Discuss
- 5. A father was 12 times as old as his son 20 years back. Now he is twice as old as his son. What are their present ages?
Options- A. Father 44 and son 22
- B. Father 55 and son 33
- C. Father 66 and son 44
- D. None of these Discuss
- 6. The age of Ram is double as that of Shyam and half as that of Suresh. If the sum of their ages is 70, what is the age of Ram?
Options- A. 20
- B. 30
- C. 40
- D. 10 Discuss
- 7. X is four years older than Y who is twice as old as Z. If the total ages of X, Y and Z be 34, how old is X?
Options- A. 8
- B. 10
- C. 12
- D. 16 Discuss
- 8. Mani is double the age of Prabhu, Ramona is half the age of Prabhu. If Mani is sixty, find out the age of Ramona.
Options- A. 20
- B. 15
- C. 10
- D. 24 Discuss
- 9. The sum of ages of mother, daughter and son is 87 years. What will be the sum of their ages after 8 years?
Options- A. 101
- B. 110
- C. 111
- D. 105 Discuss
- 10. A was twice as old as B, two years ago. If the difference in their ages be 2 years, find A's age.
Options- A. 6
- B. 8
- C. 10
- D. 4 Discuss
Problems on Ages
Search Results
Correct Answer: 20
Explanation:
Correct Answer: 15 years
Explanation:
Suppose the present age of daughter = P years
and, the present age of mother = Q years
According to questions,
5 years ago , 3 × ( the present age of daughter - 5 ) = ( the present age of mother - 5 )
3 (P ? 5) = (Q ? 5)
? 3P ? 15 = Q ? 5
? 3P ? Q = 10 .......(i)
After five years , 2 × ( the present age of daughter + 5 ) = ( the present age of mother + 5 )
2 (P + 5) = Q + 5
? 2P + 10 = Q + 5
? 2P ? Q = ?5 .......(ii)
From equations (i) and (ii) , we get
3P ? 2P = 10 ? (?5)
? P = 15 years
Hence, the present age of daughter is 15 years .
Correct Answer: 38 : 11
Explanation:
Suppose the present age of son = P years
Present age of mother = Q years
According to question,
4 (P ? 2) = Q ? 2
? 4P ? 8 = Q ? 2
? 4P ? Q = 6 ...(i)
2 (P + 6) + 10 = Q + 6
? 2P + 12 + 10 = Q + 6
? 2P ? Q = ?16 ...(ii)
From equations (i) and (ii)
P = 11
? Q = 4 × 11 ? 6 = 38
Required the present ratio of their ages = 38 : 11
Correct Answer: 50, 25
Explanation:
Correct Answer: Father 44 and son 22
Explanation:
Suppose the present age of son = P years
The present age of father = 2P years
According to question ,
20 years ago , (2P ? 20) = 12 (P ? 20)
? 2P ? 20 = 12P ? 240
? 12P ? 2P = 240 ? 20
? 10P = 220
? P = 22 years
Age of father = 2P = 2 x 22 = 44 years
Correct Answer: 40
Explanation:
Correct Answer: 16
Explanation:
Correct Answer: 15
Explanation:
Correct Answer: 111
Explanation:
Sum of ages of mother, daughter and son (i.e., 3 persons) = 87 years.
After 8 years , Sum of their ages = Sum of ages of mother, daughter and son + ( 8 x 3 ) = 87 + (8 × 3) = 87 + 24 = 111 years
Correct Answer: 6
Explanation:
Suppose the present age of B = P years
The present age of A - The present age of B = 2 years.
Therefore, the present age of A = P + 2 years
According to question,
Two years ago , 2( the present age of B - 2 years ) = the present age of A - 2 years
2 (P ? 2) = P + 2 ? 2
? 2P ? 4 = P
? 2P ? P = 4
? P = 4
Age of B = 4 years
Age of A = P + 2 = 4 + 2 = 6 years
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