Suppose the present age of Ashok is P years and that of his mother is Q years.
5 years ago ,
3 × ( age of Ashok - 5 ) = ( age of Ashok 's mother - 5 )
3 ( P ? 5 ) = ( Q ? 5 )
? 3P ? 15 = Q ? 5
? 3P ? Q = 10 ....(i)
5 years after,
2 × ( age of Ashok + 5 ) = ( age of Ashok 's mother + 5 )
2 ( P + 5 ) = ( Q + 5 )
? 2P + 10 = Q + 5
? 2P ? Q = ? 5 ....(ii)
From equations (i) and (ii) , we get
P = 15 years
Hence , the present age of Ashok is 15 years .
Here , Present age of A = 17 years
Age of B = age of A - 5 years = 17 ? 5 = 12 years
Age of C = age of B ? 4 years =12 ? 4 = 8 years
Age of D = Age of B + 3 years =12 + 3 = 15 years
According to question ,
The average age of 30 students = 15 years
Total age of 30 students = 30 × 15 = 450 years
Total age of 30 students and teacher = ( 15 + 1 ) × 31 = 496 years
? Age of teacher = Total age of 30 students and teacher - Total age of 30 students
Age of teacher = ( 496 ? 450 ) = 46 years
According to question ,
Given :- Age of Ramu = 48 years
Age of Robin = Age of Ramu - 6 years = 48 ? 6 = 42 years
Age of Rohit = Age of Robin - 14 years = 42 ? 14 = 28 years
Age of Krishna = Age of Rohit - 15 years = 28?15 =13 years
Hence , Age of Krishna is 13 years .
Let us assume 10 years ago, ages of Ram, Shyam and Mohan were 2x, 3x and 4x years respectively.
Present ages of Ram, Shyam and Mohan will be 2x + 10 , 3x + 10 and 4x + 10 years.
According to question,
2x + 10 + 3x + 10 + 4x + 10 = 93
? 9x + 30 = 93
? 9x = 93 - 30
? 9x = 63
? x = 7
The present age of mohan = 4x + 10 = 4x7 + 10 = 38 years
Suppose the age of Johnny is P years and that of Rahul is Q years.
According to question ,
Age of Hari = 2 × Age of Johnny = 2P
And age of Hari = 5 × Age of Rahul = 5Q
? 2P = 5Q
? 2P ? 5Q = 0 ........(i)
Again age of Johnny = Age of Rahul + 3 years
? P = 3 + Q
? P ? Q = 3........ (ii)
On solving equations (i) and (ii), we get
Q = 2
? Age of Johnny = 3 + Q = 3 + 2 = 5 years
Hence , the age of Johnny is 5 years .
Suppose the age of daughter is P years.
Age of brother = age of daughter + 5 years = P + 5 years
Age of mother = 2 × age of daughter = 2P years
According to question ,
? Age of mother - 20 years = Age of brother
? 2P ? 20 = P + 5
? 2P ? P = 5 + 20
? P = 25 years
Age of mother = 2P = 2 × 25 = 50 years
Age of father = Age of mother + 10 years = 50 + 10 = 60 years
Suppose the present ages of Ashu and her mother be P and Q years respectively.
According to question,
5 years ago , 3 × ( ages of Ashu - 5 ) = ages of Ashu's mother - 5
? 3 ( P - 5 ) = Q - 5
? 3P - 15 = Q - 5
? 3P - Q = 10 ... (i)
Again, After 5 years , 2 × ( ages of Ashu + 5 ) = ages of Ashu's mother + 5
? 2(P + 5) = Q + 5
? 2P + 10 = Q + 5
? 2P ? Q = - 5.... (ii)
From equations (i) and (ii) , we get
P = 15 years
Therefore, Ashu is 15 year old at present.
Here , Father = F , Mother = M and Daughter = D
According to question
Age of F = Age of M + 5,
Age of M = 3 × Age of D and Age of D = 10 years
? Age of M = 3 × 10 = 30 years
Therefore, father's present age = 30 + 5 = 35 years
Required answer = father's present age - 10 years = 35 ? 10 = 25 years
Suppose the age of Shyam = P years
According to question ,
Age of Ram = 2 × age of Shyam = 2P years
Age of Sohan = 4 × age of Shyam = 4P years
? Shyam > Mohan
So, Sohan (4P) > Ram (2P) > Shyam (P) > Mohan
? Sohan is the oldest.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.