As 'Cow' eats vegetarian foods, therefore she is 'Herbivorous'. Similarly, 'Tiger' eats fleshy foods and therefore a tiger is 'Carnivorous'.
and (3)2 + (4)2 + (6)2 + (2)2 = 65 x 10 = 650
Similarly (0)2 + (1)2 + (2)2 + (8)2 = 69 x 10 = 690.
6 | 3.0 | 4.5 | 2.25 | 4.0 | 12 |
40 | (a) | (b) | (c) | (d) | (e) |
Which of the following numbers will come in place of (c)? |
The given series is in the below pattern ,
First series :-
First term = 6
Second term = First term ÷ 2
? Second term = 6 ÷ 2 = 3
Third term = Second term × 1.5
? Third term = 3 × 1.5 = 4.5
similarly , we can calculate the all next terms .
........... and so on.
Second series :-
First term = 40
Second term = First term ÷ 2
? Second term = 40 ÷ 2 = 20
Third term = Second term × 1.5
? Third term = 20 × 1.5 = 30
Fourth term = Third term ÷ 2
? Fourth term = 30 ÷ 2 = 15
Hence , the place value of (c) is 15 .
and (3)2 + (9)2 = 90
Therefore (1)2 + (5)2 = 26.
4 | 9 | 25 | 103 | ||
3 | (a) | (b) | (c) | (d) | (e) |
Which of the following numbers will come in place of (c)? |
The given series is in the below pattern ,
First series :-
First term = 4
Second term = First term × 2 + 1
? Second term = 4 × 2 + 1 = 9
Third term = Second term × 3 - 2
? Third term = 9 × 3 - 2 = 25
similarly , we can find the all others terms .
......... and so on .
Second series :-
First term = 3
Second term = First term × 2 + 1
? Second term = 3 × 2 + 1 = 7
Third term = Second term × 3 - 2
? Third term = 7 × 3 - 2 = 19
Fourth term = Third term × 4 + 3
? Fourth term = 19 × 4 + 3 = 79
Hence , the place value of ( c ) is 79 .
and (4 x 9) = 36 and (2 x 9) = 18
Therefore (9 x 6) = 54 and (4 x 6) = 24.
7 | 4 | 5 | 9 | 20 | 52.5 |
3 | (a) | (b) | (c) | (d) | (e) |
Which of the following numbers will come in place of (c)? |
As per the details in the question the series is in the form of
First series :-
First term = 7
Second term = First term × 0.5 + 0.5
? Second term = 7 × 0.5 + 0.5 = 4
Third term = Second term × 1 + 1
? Third term = 4 × 1 + 1 = 5
similarly , we can find the all others terms .
Second series :-
First term = 3
Second term = First term × 0.5 + 0.5
? Second term = 3 × 0.5 + 0.5 = 2
Third term = Second term × 1 + 1
? Third term = 2 × 1 + 1 = 3
Fourth term = Third term × 1.5 + 1.5
? Fourth term = 3 × 1.5 + 1.5 = 6
Hence , the place value of ( c ) is 6 .
and (6 x 4) + 5 = 29
Therefore, (7 x 5) + 6 = 41
3 | 12 | 30 | 66 | 138 | 282 |
7 | (a) | (b) | (c) | (d) | (e) |
Which of the following numbers will come in place of (b)? |
As per the details in the question the series is in the form of
First series :-
First term = 3
Second term = First term × 2 + 6
? Second term = 3 × 2 + 6 = 12
Third term = Second term × 2 + 6
? Third term = 12 × 2 + 6 = 30
similarly , we can find the all others terms .
Second series :-
First term = 7
Second term = First term × 2 + 6
? Second term = 7 × 2 + 6 = 20
Third term = Second term × 2 + 6
? Third term = 20 × 2 + 6 = 46
Hence , the place value of ( b ) is 46 .
2 | 3 | 7 | 25 | 121 | 721 |
3 | (a) | (b) | (c) | (d) | (e) |
Which of the following numbers will come in place of (c)? |
The series is × 2 ?1, × 3 ? 2, × 4 ? 3,.....
The given series is in the below pattern ,
First series :-
First term = 2
Second term = First term × 2 - 1
? Second term = 2 × 2 - 1 = 3
Third term = Second term × 3 - 2
? Third term = 3 × 3 - 2 = 7
similarly , we can calculate the all next terms .
Second series :-
First term = 3
Second term = First term × 2 - 1
? Second term = 3 × 2 - 1 = 5
Third term = Second term × 3 - 2
? Third term = 5 × 3 - 2 = 13
Fourth term = Third term × 4 - 3
? Fourth term = 13 × 4 - 3 = 49
Hence , the place value of ( c ) is 49 .
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