Volumes of the same book are not to be separated i, e. all volumes of the same book are to be kept together, Regarding all volumes of the same book as one book, we have only 4 + 1 + 1 + 1 = 7 books.
These seven books can be arranged in 7! ways. The book having 8 volumes can be arranged among themselves in 8! ways, the book having 5 volumes can be arranged among themselves in 5! ways, and the book having 3 volumes can be arranged among themselves in 3! ways.
? Required number = 7! 8! 5! 3!
Let sum be P.
? 50% of P = P/2 = SI
Now, P/2 = (P x 5 x T) / 100 [ as time = 10 yr]
? P/2 = 5PT / 100
? 1/2 = T/20
? = T = 10 yr
Increase in circumference of circle = 5%
? Increase in radius is also 5%.
Now, increase in area of circle = 2a + (a2/100) %
Where, a = increase in radius= 2 x 5 + (5 x 5)/100 % = 10.25%
Let the number of failed student = Y
? Number of passed student = 80 - Y
sum of marks of all students = sum of marks of passed students + sum of marks of failed students
80 x 40 = (80 - Y) x 60 + 35Y
? 3200 =4800 - 60Y + 35Y
? 25Y = 1600
? Y = 64
? Number of students who failed = 64
2 men = 7 boys
? 1 man = 7/2 days
5 women = 7 boys
? 1 women = 7/5 boys
7 men + 5 women + 2 boys = 7 x 7/2 + 5 x 7/5 + 2 = 67/2 boys
Now, B1 x D1 = B2 x D2
7 X 469 = 67/2 x D2
D2 = 98 days
Let the value for ? be N
So N x 9 x 7 x 3 = a number with unit digit 1.
Clearly, the minimum value of N is 9.
Given expression = [(272 - 32) (124 + 176)] / (17 x 15 - 15)
= (240 x 300 ) / 240
= 300
Average = (8 + 9 + 12 + 13 + 15 + 9)/6
= 66 / 6
= 11
? Relative speed of the train = 60 + 6 = 66 km/hr
= 66 x 5/18 m/sec = 55/3 m/sec
? Required time = 110 x (3/55) = 6 sec
Given, length of four metal roads are 78, 104, 117 and 169 cm.
Now,
78 = 13 x 2 x 3,
104 = 13 x 2 x 2 x 2,
117 = 13 x 3 x 3,
169 = 13 x 13
Length of each piece of rod as long as possible, HCF = 13 CM
? Number of piece = 6 + 8 + 9 + 13 = 36
Speed = 30 km/hr = 30 x (5/18) = 25/3 m/sec.
? Length of the train = (25/3) x (27/2)
= 225/2 = 1121/2 metres
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