Discussion
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- Question
- In how many different ways, the letters of word 'FINANCE' can be arranged?
Options- A. 5040
- B. 2040
- C. 2510
- D. 4080
- Correct Answer
-
ExplanationTotal number of letters = 7, but N has come twice.
So, required number of arrangements = 7 ! / 2 !
= [7 x 6 x 5 x 4 x 3 x 2! ] / 2!
= 2520 - 1. In how many ways, the letters of the word 'BANKING' can be arranged?
Options- A. 5040
- B. 2540
- C. 5080
- D. 2520 Discuss
- 2. In how many ways, the letters of the word 'STRESS' can be arranged?
Options- A. 360
- B. 240
- C. 720
- D. 120 Discuss
- 3. In how many ways, the letters of the word 'ARMOUR' can be arranged?
Options- A. 720
- B. 300
- C. 640
- D. 350 Discuss
- 4. In how many different ways, can the letters of the word 'INHALE' be arranged?
Options- A. 720
- B. 360
- C. 120
- D. 650 Discuss
- 5. If nP 3 = 9240, then find the value of n.
Options- A. 20
- B. 21
- C. 22
- D. 23 Discuss
- 6. In how many different ways, can the letters of the word 'VENTURE' be arranged?
Options- A. 840
- B. 5040
- C. 1260
- D. 2520 Discuss
- 7. In a meeting between two countries, each country has 12 delegates. All the delegates of one country shake hands with all delegates of the other country. Find the number of handshakes possible?
Options- A. 72
- B. 144
- C. 288
- D. 234 Discuss
- 8. How many straight lines can be drawn from 15 non-collinear points?
Options- A. 105
- B. 120
- C. 110
- D. 115 Discuss
- 9. A library has 'a' copies of one book, 'b' copies of each of two book, 'c' copies of each of three books and single copy of 'd' book. The number of ways in which these books can be distribute is?
Options- A. (a + b + c + d)! / (a! b! c!)
- B. (a + 2b + 3c + d)! / {a! (b!)2 (c!)3}
- C. (a + 2b + 3c + d )! / (a! b! c!)
- D. None of these Discuss
- 10. The number of triangles that can be formed by choosing the vertices from a set of 12 points, seven of which lie on the same straight line, is?
Options- A. 185
- B. 175
- C. 115
- D. 105 Discuss
Permutation and Combination problems
Search Results
Correct Answer: 2520
Explanation:
Total letters = 7, but N has come twice.
So, required number of arrangements = 7 ! / 2 !
= [7 x 6 x 5 x 4 x 3 x 2 ! ] / 2 ! = 2520
Correct Answer: 120
Explanation:
Required number of arrangements = 6 ! / 3 ! [? S has come thrice ]
= [ 6 x 5 x 4 x 3! ] /3 !
= 120
Correct Answer:
Explanation:
Number of arrangements n ! /( p ! q ! r ! )
Total letters = 6, but R has come twice.
So, required number of arrangements
= 6 ! / 2 ! = (6 x 5 x 4 x 3 x 2 !) / 2 ! = 360
Correct Answer: 720
Explanation:
The word 'INHALE' has 6 distinct letters.
? Number of arrangements = n ! = 6 !
= 6 x 5 x 4 x 3 x 2 x 1
= 720
Correct Answer: 22
Explanation:
nP3 = 9240 ? n! / (n-3)! = 9240
? n(n - 1)(n - 2) = 9240
? n(n - 1)(n - 2) = 22 x 21 x 20
? n = 22
Correct Answer: 2520
Explanation:
The required different ways = 7 ! / 2 !
= 7 x 6 x 5 x 4 x 3 x 2!/2!
= 2520
Correct Answer: 144
Explanation:
Total number of handshakes = 12 x 12 = 144
Correct Answer: 105
Explanation:
Required number of lines = nC2
= 15C2
= (15 x 14)/2
= 105
Correct Answer: (a + 2b + 3c + d)! / {a! (b!)2 (c!)3}
Explanation:
Total number of books = a + 2b + 3c + d . Since there are 'b' copies of each of two books, 'c' copies of each of three books and single copy of 'd' book.
Therefore, the total number of arrangements is = (a + 2b + 3c + d )! / {a! (b!)2 (c!)3}
Correct Answer: 185
Explanation:
Required no. of triangles = 12C3 - 7C3 = 185
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