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- Question
- A bag contains 8 red and 5 white balls. 2 balls are drawn at random. What is the probability that both are white?
Options- A. 5/16
- B. 2/13
- C. 3/26
- D. 5/39
- Correct Answer
- 5/39
Explanationn(S) = Number of ways of drawing 2 balls out of 13 = 13C2 = 13 x 12 / 2= 78
n(E) = No. of ways of drawing 2 balls out of 5 = 5C2 = 5 x 4 / 2 = 10
? P(E) = n(E)/n(S) = 10/78 = 5/39 - 1. The odds against the occurrence of an event are 5 : 4. The probability of its occurrence is?
Options- A. 4/5
- B. 4/9
- C. 1/5
- D. 1/4 Discuss
- 2. Ticket numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn bears a number which is a multiple of 3 or 7?
Options- A. 1/15
- B. 1/2
- C. 2/5
- D. 7/20 Discuss
- 3. When two dice are rolled, what is the probability that the sum of the numbers appeared on them is 11?
Options- A. 1/6
- B. 1/18
- C. 1/9
- D. 1 Discuss
- 4. The probability of getting a composite number when a six-faced unbiased die is tossed, is
Options- A. 1/4
- B. 1/3
- C. 1/2
- D. 1 Discuss
- 5. The probability of drawing a red card from a deck of playing cards is
Options- A. 2/18
- B. 1/13
- C. 1/4
- D. 1/2 Discuss
- 6. A bag contains 6 black balls and 8 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
Options- A. 4/7
- B. 3/4
- C. 4/5
- D. 1/8 Discuss
- 7. Three unbiased coins are tossed. What is the probability of getting at most 2 heads?
Options- A. 1/4
- B. 3/8
- C. 7/8
- D. 1/2 Discuss
- 8. Three unbiased coins are tossed, what is the probability of getting exactly two heads?
Options- A. 1/3
- B. 3/4
- C. 2/3
- D. 3/8 Discuss
- 9. In a simultaneous throw of two coins, the probability of getting at least one head is?
Options- A. 1/2
- B. 2/3
- C. 3/4
- D. 1/3 Discuss
- 10. In a throw of a coin, the probability of getting a head is?
Options- A. 1/2
- B. 1/4
- C. 1
- D. None of these Discuss
Probability problems
Search Results
Correct Answer: 4/9
Explanation:
Number of cases favourable of E = 4
Total Number of cases = (5 + 4 ) = 9
? P(E) = 4/9
Correct Answer: 2/5
Explanation:
Clearly, n(S) = 20 and E = { 3, 6, 9, 12, 15, 18, 7, 14 } i.e., n(E) = 8
? P(E) = n(E)/ n(S) = 8/20 = 2/5
Correct Answer: 1/18
Explanation:
n(S) = 36
n(E) = {(5,6), (6,5)} = 2
? p(E) = n(E) / n(S) = 2/36 = 1/18
Correct Answer: 1/3
Explanation:
n(S) = 6, n(E) = (4, 6) = 2
? P(E) = 2/6 = 1/3
Correct Answer: 1/2
Explanation:
Total number of cards n(S) = 52
Number of red cards n(E) = 26
? P(E) = n(E)/n(S) = 26/52 = 1/2
Correct Answer: 4/7
Explanation:
Total no. of balls = (6 + 8) = 14
No. of white balls = 8
? P(drawing a white ball) = 8/14 = 4/7
Correct Answer: 7/8
Explanation:
? n(S) = (2)3 = 8
E = Event of getting 0, or 1 or 2 heads
= {TTT, TTH, THT, HTT, HHT, HTH, THH}
? n(E) = 7
? P(E) = n(E)/n(S) = 7/8
Correct Answer: 3/8
Explanation:
S= { HHH, HHT, HTH, THH, TTH, THT, HTT, TTT} and
E = Event of getting exactly two heads = {HHT, HTH, THH}
? P(E) = n(E)/n(S) = 3/8
Correct Answer: 3/4
Explanation:
S = {HH, HT, TT, TH}
and E = {HH, HT, TH }
? P(E) = n(E)/n(S) = 3/4
Correct Answer: 1/2
Explanation:
Here S = {H, T}
and E = {H}
? P(E) = n(E)/n(S) = 1/2
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