Probability of getting head in one trail = 1/2
? Reqd Probability of getting heads in both the trails = 1/2 x 1/2 = 1/4
Number of cases favourable of E = 3
Total Number of cases = (3 + 5 ) = 8
? P(E) = 3/8
P (getting a prize ) = 20 / (20 + 15 ) = 20 / 35 = 4/7
P (red) = 9 / (9 + 7 + 4) = 9/20
? P(not-red) = (1 - 9/20) = 11/20
S = {1, 2, 3, ......16}
E = {2, 3, 5, 7, 11, 13}
? P(E) = n(E)/n(S) = 6/16= 3/8
? 3000 = 2000(1 + r/200)6
? 3/2 = (1 + r/200)6
? 1 + r/200 = (3/2)1/6
? log(1 + r/200)= 1/6(log 3 - log 2 )
? log(1 + r/200)= 1/6(0.4771-.3010)
= 0.02935
? (1 + r/200) = antilog(.02935)
? 1 + r/200 = 1.070 = 1 + 7/100
? r = 14%
? Total no. of favourable cases i,e., (5, 10, 15, 20, 25, 30, ....., 105, 110, 115, 120) = 24.
? Reqd . Prob = 24/120 = 1/5
No of white balls = 7
Red balls = 9
Total no. of balls = 7 + 9 = 16
Probability of drawing a white ball = 7/16
Total ways = 52
There is one queen of club and one king of heart favourable ways = 1 + 1 = 2.
? Required probability = 2/52 = 1/26
Here, n(5) = {a, e, i,o, u}
and E = Event of selecting the vowel i = {i}
? P(E)= n(E)/n(S) = 1/5
Required probability = P(A) x P(B)
= (7/8) x (9/10)
= 63/80
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