? log5[(x2 + x ) / x] = 2
? log10(x + 1) = 2
? x + 1 = 25
? x = 24
Since, 0.3274 gives characteristic 1. Therefore value of log (0.3274) = 1.5150
? log tan 45 = log 1 = 0
Hence, Whole Expression = (something) x zero
Given Exp.
= log (57 x 100 / 100) + 3log(0.57) + 1/2log(0.57)
= log (0.57) + log 102 + 3log(0.57) +1/2log (0.57)
= (1 + 3 + 1/2) log(0.57) + 2 [? log102 = 2]
= (4.5 x 1.756) + 2 = 4.5 x (-1 + 0.756) + 2
= 3.402 - 4.5 + 2
= 0.902
? log1227 = a
? log 27 / log 12 = a
? a log 12 = log 33
? a log ( 3 x 4 ) = 3 log 3
? a[log 3 + log 4] = 3 log 3
? a log 4 + a log 3 = 3 log 3
? a log 22 = ( 3 - a) log 3
? 2a log 2 = (3 - a) log 3
? log 2 / log 3 = (3 - a) / 2a
Now log616 = log16 / log 6 = log 24 / log (2 x 3) = 4 log 2 / ( log 2 + log 3)
= [4 (log 2 / log 3)] / [(log 2 / log 3) + 1]
= 4[(3 - a) / 2a] / [{(3 - a) / 2a } + 1]
= 4(3 - a) / (3 + a)
logx4 = log 4 / log x = 2/5
? 2log2 / log x = 2/5
? log x =5log 2 = log 25
? log x = log 32
? x = 32
? loga, logb, logc are in A.P. Then,
? logb - loga = logc - logb
? log b/a = log c/b
? b/a = c/b
? b2 = ac
? a, b, c are in G.P.
? A = 12,000(1 + 12/100)10
= 12000(28/25)10
? log A = log 12000 + 10[log 28 - log 25]
? log A = 4.0792 + 10(1.4472 - 1.3979)
= 4.0792 + 0.493
= 4.5722
? A = antilog 4.5722 = 37342
C.I. = 37342 - 12000 = 25342
=25350
? x = 264
? log x = log 264
? log x = 64 log 2
= 64 x .3010 = 19.264
? No.of digits = 19 + 1 = 20
Let N = 312 x 28
? log N = 12 x log3 + 8 x log 2
? log N = 12 x 0.47712 + 8 x 0.30103
? log N = 8.13368
? No.of digits = 8 + 1 = 9
Given exp. = 1/(log2 ?) + 1/(log6 ?)
= log? 2 + log? 6
= log? (2 x 6)
= log?12
Since 12 > ? so the value of given expression is more than 1.
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