A = log27625 + 7log1113
= log3354 + 7 log1113
= 4/3 log3 5 + 7 log1113
B = log9125 + 13 log117 = log32 53 + 13 log117
= 3/2 log3 5 +13 log11 7
Let log3 5 = x and by the above rule
7 log11 13 = 13 log11 7
Therefore, A = 4/3 x + 13 log11 7
and B = 3/2 x + 13 log11 17
clearly, A < B hence (B) is the correct answer.
logan / logabn = [( log n / log a) / (log n / log (a.b))]
= log (a.b) / log a
= ( log a + log b) / log a
= 1 + (log b / log a)
= 1 + logab
? 10x = 1730/1000
? log10x= log101730 - log101000
? x = 3.2380 - 3
= 0.2380
Given Exp. = log927 - log279
= log27 / log9 - log9 / log27
= 3log3 / 2log3 - 2log3 / 3log3
= 3/2 - 2/3 = 5/6
(log53) x log3 54 = [log3 / log5] x 4 x [log5 / log3]
= 4
If log 125 / log 5 = x
then x = 3log5 / log5= 3
810 = (23)10
? Required answer = [30 log10 2 + 1]
= [30 x 0.3010] + 1
= 9.03 + 1
= 9 + 1
= 10
857 = (23)57 = 2171
? Required answer = (171 log10 2 + 1 )
= [171 x 0.3010] + 1 = [51.4710] +1
= 51+1 =52
Given log( x - 5) = log(x) - log(5)
? x -5 = x/5
? x = 25/ 4 ....(i)
Again from question
log(y - 6) = log(y) - log(6)
? y - 6 = y/6
? y = 36/5 ...(ii)
From equations (i) & (ii) x < y
Given log (x + 4) = log(4) + log(x)
? x + 4 = 4x
? x = 4/3
Similarly y = 5/4
? x > y
? ax = b
? loga b = x
? by = c
? logb c = y
? cz = a
? logc a = z
? xyz = logab x logbc x logca = 1
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