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  • Question
  • If log 2 = 0.3010 then log 5 equals to?


  • Options
  • A. 0.3010
  • B. 0.6990
  • C. 0.7525
  • D. Given log 2, it is not possible to calculate log 5

  • Correct Answer
  • 0.6990 

    Explanation

    log 5 = log 10 /2 = log 10 - log 2
    = 1 - 0.3010 = 0.6990


  • Logarithm problems


    Search Results


    • 1. 
      The simplified form of log(75/16) -2 log(5/9) +log(32/343) is?

    • Options
    • A. log 2
    • B. 2 log 2
    • C. log 3
    • D. log 5
    • Discuss
    • 2. 
      The value of log 9/8 - log 27/32 + log3/4 is?

    • Options
    • A. 0
    • B. 1
    • C. 2
    • D. 3
    • Discuss
    • 3. 
      Given that log 10 2 = 0.3010, then log 2 10 is equal to?

    • Options
    • A. 0.3010
    • B. 0.6990
    • C. 1000 / 301
    • D. 699 / 301
    • Discuss
    • 4. 
      The value of log 23 x log 32 x log 34 x log 43 is?

    • Options
    • A. 1
    • B. 2
    • C. 3
    • D. 4
    • Discuss
    • 5. 
      The value of $ \frac{\log_{a}{x}}{\log_{ab}{x}} - \log_{a}{b}$ is?

    • Options
    • A. 0
    • B. 1
    • C. a
    • D. ab
    • Discuss
    • 6. 
      If log 102 =0.3010 and log 107 = 0.8451, then the value of log 10 2.8 is?

    • Options
    • A. 0.4471
    • B. 1.4471
    • C. 2.4471
    • D. 14.471
    • Discuss
    • 7. 
      If log 10 2 =0.301, then the value of log 10(50) is?

    • Options
    • A. 0.699
    • B. 1.301
    • C. 1.699
    • D. 2.301
    • Discuss
    • 8. 
      Find the value of log (a 2 / bc) + log (b 2 / ac) + log (c 2 / ab)?

    • Options
    • A. 0
    • B. 1
    • C. abc
    • D. ab2c2
    • Discuss
    • 9. 
      Find the value of log 8 + log 1/8?

    • Options
    • A. 0
    • B. 1
    • C. 2
    • D. log (64)
    • Discuss
    • 10. 
      The equation log ax + log a (1+x)=0 can be written as?

    • Options
    • A. x2 + x - 1 = 0
    • B. x2 + x + 1 = 0
    • C. x2 + x - e = 0
    • D. x2 + x + e = 0
    • Discuss


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