Given Exp. = log [{(9/8) / (27/32)} x 3/4)]
= log [(9/8) x (3/4) x (32/27)]
= log 1
= 0
log2 10 = log 10 / log 2
= 1 / log 2
= 1.0000 / 0.3010
= 1000 / 301
Given Exp.= log23 x log 32 x log34 x log43
= (log3 / log2) x ( log2 / log3) x (log4 / log3) x (log3 / log4) = 1
? loga x = ( logabx) / (logaba)
? The given expression = [[(logabx) / (logaba)] / [( logabx )] - ( logab)
= (1/logaba) - logab = logaab - logab = loga(ab/b)
= logaa = 1
Required answer = [64 log10 2] + 1
= [ 64 x 0.3010 ] + 1
= 19.264 + 1
= 19 + 1
= 20
Given Exp. = log75/16 - 2 log5/9 + log32/343
= log [(25 x 3) / (4 x 4)] - log (25/81) + log [(16 x 2) / (81 x 3)]
= log(25 x 3) - log ( 4 x 4 ) - log(25) + log81 + log(16 x 2) -log (81 x 3)
= log 25 + log 3 - log 16 - log 25 + log 81 + log 16 + log 2 - log 81 - log 3
= log 2
log 5 = log 10 /2 = log 10 - log 2
= 1 - 0.3010 = 0.6990
log102.8 = log10(28/10)
= log 28 - log 10
= log (7 x 4 ) - log 10
= log 7 + 2 log 2 - log 10
= 0.8451 + 2 x 0.3010 - 1
= 0.8451 + 0.6020 - 1
= 0.4471
log1050 = log10[(50 x 2) / 2]
= log 100 - log 2
= log10102 - log 2
= 2 - 0.301
= 1.699
Given Exp. = log (a2 / bc) + log (b2 / ac) + log (c2 / ab)
= log [(a2 x b2 x c2) / (a2 x b2 x c2)]
=log 1
=0
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