Draw a figure as per given question,
In a Right triangle ADC, Use the (Pythagoras Theorem)
AC = ?DC2 - AD2
? AC = ? 152 - 9 2
? AC = ? 225 - 81
? AC = ? 144
? AC = 12 cm
In a Right triangle BCE, Use the formula
CB = ? CD2 - BE2
? CB = ?15 2 - 122
? CB = ?225 - 144
? CB = ? 81
? CB = 9 m
? Width of the street (AC + BC) = AB = 12 + 9 = 21 m.
In ?ACE
?A + ?C + ?E = 180°
Similarly in ?DFB
?D + ?F + ?B = 180°
? (?A + ?C + ?E) + (?D + ?F + ?B) = 360°
?A + ?B + ?C + ?D + ?E + ?F = 360°
Let, the angle be A
? Its complement angle = 90° ? A
According to the question
(90 ? A) = A + 60°
? 90 - 60 = A + A
? 2A = 30°
? A = 15°
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