Let a be the first term and and r be the common ratio of the GP. From the given problem,
a + arn - 1 = 66 ...(i)
Also, ar x arn - 2 = 128 ? a2rn - 1 = 128 ... (ii)
From Eq. (ii),
a.arn - 1 = 128
arn - 1 = 128/ a
On substitution this in Eq.(i), we get
a + 128/a = 66
a2 - 66a + 128 = 0
a = [-b ± ?b2 - 4ac] /2a
= 66 ± ?662 - 4 x 128 x 1)/2 = 64 or 2
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
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