Curved surface area of cylinder = 2?rh cm2
Total surface area of cylinder = 2?r(h + r) cm2
Now, According to the question
2?rh/2?r(h + r) = 1/2
? h/(h + r) = 1/2
? 2h = h + r
? Now, Total surface area = 616 cm2
? 2? (h + r) = 616
? 2?r (r + r) = 616 (? h = r)
? 2?r(2r) = 616
? 4?r2 = 616
? r = ?style="text-decoration:overline">616/4?
= ?616 x 7/4 x 22
= ?7 x 7 =
? r = h = 7 cm
? Volume = ? r2 h
= (22/7) x (7 x 7) x 7 = 1078 cm3
External radius = 2.5 cm,
length = 100 cm
? External volume = [? x (2.25)2 x 100] cm2
internal radius = 1.5 cm
? internal volume = [? x (1.5)2 x 100]cm3
Volume of metal
= [? x (2.5)2 x 100 - ? x (1.5)2 x 100] cm3
= ? x 100 x [(2.5)2 - (1.5)2] cm3
= (22/7 x 100 x 4 x 1 x 21/1000) kg
= 26.4 kg.
Let the side of the cube be 3k, 4k and 5k, respectively.
So, volumes of these cubes are 27 k3, 64k3, 125 k3 respectively.
? Volume of the new bigger cube = 27 k3 + 64k3 + 125 k3
= 216k3
So, side of the new cube = 6k
Since, diagonal of the cube = ?(6k)2 + (6k)2 + (6k)2
= 12?3
? 108k2 = 432
?k = 2
So, sides of the three cubes were 6 cm, 8 cm and 10 cm respectively.
Let h be the height,
Volume of the cone = V
and curved surface area of the cone = c
? 1/3 ?r2h = V, ?rl = c
i.e., ?r?r2 + h2 = c
?2r2(r2 + h2) = c2
Consider 3?Vh3 - c2h2 + 9V2
= 3? x 1/3?r2h x h3 - ?2r2(r2 + h2)h + 9 x 1/9 x ?2r4 h2
= ?2r2h4 - ?2r4h2 - ?2r2h4 + ?2r4 = 0
Height of the cylinder = 10 x Diameter of each ball
= 10 x 10 = 100 cm
? Required empty space
= ? (5)2 (100) - 4/3 ? (5)3 x 10
= ? (5)2 x 10 [10 - 20/3]
= ? (5)2 x 10 [30 - 20/3] = 2500/3 ? cm3
Given that, Height = 1 m
Diameter = 140 cm or 140/100 m = 1.40 m
? r = 1.40/2 = 0.7 m
Now,
Required sheet = Total surface area = 2?r( h + r)
= (22/7) x 1.4 x (1 + 0.7) = 7.48 sq m
? Sheet required = 7.48 sq m
If 10 circular plates each of thickness 3 cm, each are placed one above the other, then it forms a cylinder with height (3 x 10 = 30 cm) and a hemisphere of radius 6 cm is placed on the top just to cover the cylinder that means its radius is 6 cm also
? Radius of hemisphere (R) = 6 cm
Radius of cylinder (r) = 6 cm
and height of cylinder (h) = 30 cm
? Volume of the solid = Volume of cylinder + Volume of hemisphere
= ?r2h + (2/3)?R3
= ?(6)2 x 30 + (2/3)?(6)3
= ? x 36 x 30 + (2/3)? x 216
= 1080? + 2? x 72 = 1080? + 144?
= 1224? cm3
Which is the required volume of solid.
Given series is a consecutive prime number series. Therefore, the next term will be 23.
Series Pattern
+6, +9, +12, +15....
? Missing term = 6 + 6 = 12
(1 - 2) = -1
(3 - 4) = -1
(5 - 6) = -1
and so on.
? Total terms of -1 will be 50.
? Answer = -1 x 50 = -50
A = (a + b)/2,
1/H = (1/a + 1/b)/2
? H = 2ab/(a +b),
G = ?ab
? A x H = {(a + b)/2} x {2ab/(a + b)} = ab = G2
? A x H = G2
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