Radius of cone (r) = 6/2 = 3 cm
and height of cone (h) = 4cm
Slant height (l) = ?h2 + r2
= ?(4)2 + (3)2
= ?16 + 9
= 5 cm
Now, curved surface area = ?rl
= (22/7) x 3 x 5
= 330/7 = 47 cm2
Volume of cone = (1/3)?r2h
= (1/3) x (22/7) x 10 x 10 x 21 = 2200 cm3
Given that,
Diameter of a right circular cone = 7 cm
? Radius of a right circular cone = 7/2 cm
and slant height of a right circular cone (l) = 10 cm
? Lateral surface area of a cone = ?rl = (22/7) x (7/2) x 10
= 11 x 10 = 110 cm2
Curved surface area of right circular cone = ?rl
? 440 = (22/7) x 14 x l
? l = (440 x 7) / (22 x 14) = 10 cm
Volume of the cylinder = ?r2h
= (22/7) x 7 x 7 x 500 = 77000
= (77 x 103) cm3
Curved surface area = 2?rh
= 2 x (22/7) x 0.25 x 3.5
= 5.5 sq m
? Cost of painting 5.5 sq m = 10 x 5.5
= ? 55
Volume = (1/3)?r2h
According to the question,
(1/3)?r2h = 100?
? (1/3)?r2 x 12 = 100?
? r2 = 25
? r = ?25 = 5 cm
? Slant height (l) = ?h2 + r2
= ?122 + 52
= ?169 = 13 cm
volume = 48 ? cm3 and h = 9 cm
? (1/3)?r2h = 48?
? (1/3) x ? x r2 x 9 = 48?
? r2 = (48? x 3) / (? x 9) = 16
? r = ?16 = 4 cm
? Diameter = 2r = 2 x 4 = 8 cm
Slant height (l) = ?r2 + h2
=?72 + 242
= ?49 + 576
= ?625
= 25 cm
Curved surface area = ?rl = (22/7) x 7 x 25 = 550 sq cm
? Area of 5 caps = 550 x 5 = 2750 sq cm
In first situation.
Radius = r1, height = h1 and volume = v1
In second situation,
Radius =2r1, height = h2 and volume = v2
In the volume is fixed, then
v1 = v2
? (1/3)?r21h1 = (1/3)?(2r1)2h2
? h1 = 4h2
? h2 = h1/4
Therefore, height of the the cone will be one-fourth of the previous height.
Given, l = 9 m
and diameter = 14 m ? r = 14/2 = 7 m
Now, volume = (1/3)?r2h
= (1/3)? x 49 x ?l2 - r2
= (1/3)? x 49 x ?81 - 49
= (1/3) x 49? x ?32 = 49??32 /3 m3
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