Given that,
Diameter of a right circular cone = 7 cm
? Radius of a right circular cone = 7/2 cm
and slant height of a right circular cone (l) = 10 cm
? Lateral surface area of a cone = ?rl = (22/7) x (7/2) x 10
= 11 x 10 = 110 cm2
Curved surface area of right circular cone = ?rl
? 440 = (22/7) x 14 x l
? l = (440 x 7) / (22 x 14) = 10 cm
Volume of the cylinder = ?r2h
= (22/7) x 7 x 7 x 500 = 77000
= (77 x 103) cm3
Curved surface area = 2?rh
= 2 x (22/7) x 0.25 x 3.5
= 5.5 sq m
? Cost of painting 5.5 sq m = 10 x 5.5
= ? 55
In one revolution, area covered = Covered surface area
? 2?rh = 2 x (22/7) x 42 x 120 = 31680 sq cm
in 500 revolutions,
Area covered = 31680 x 500 = (1584 x 104) sq cm
= (1584 x 104) / (104) = 1584 sq m
Area of 4 wails = Lateral surface area perimeter = 2(l + b) = 250
? l + b = 250/2 = 125 m
Area to be painted = Cost/Rate = 15000/10 = 1500 sq m
Area of 4 wails = 2(l + b)h = 250 h
? 250h = 1500
? h = 1500/250 = 6 m
Volume of cone = (1/3)?r2h
= (1/3) x (22/7) x 10 x 10 x 21 = 2200 cm3
Radius of cone (r) = 6/2 = 3 cm
and height of cone (h) = 4cm
Slant height (l) = ?h2 + r2
= ?(4)2 + (3)2
= ?16 + 9
= 5 cm
Now, curved surface area = ?rl
= (22/7) x 3 x 5
= 330/7 = 47 cm2
Volume = (1/3)?r2h
According to the question,
(1/3)?r2h = 100?
? (1/3)?r2 x 12 = 100?
? r2 = 25
? r = ?25 = 5 cm
? Slant height (l) = ?h2 + r2
= ?122 + 52
= ?169 = 13 cm
volume = 48 ? cm3 and h = 9 cm
? (1/3)?r2h = 48?
? (1/3) x ? x r2 x 9 = 48?
? r2 = (48? x 3) / (? x 9) = 16
? r = ?16 = 4 cm
? Diameter = 2r = 2 x 4 = 8 cm
Slant height (l) = ?r2 + h2
=?72 + 242
= ?49 + 576
= ?625
= 25 cm
Curved surface area = ?rl = (22/7) x 7 x 25 = 550 sq cm
? Area of 5 caps = 550 x 5 = 2750 sq cm
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