If the radius of a sphere is doubled, then its volume is increased by?

Original volume = 1/3 ?r²h;
New volume = 1/3 ?r²(2h) = 2/3?r²h

Required increased % = [?r²h/3]/[?r²h/3] x 100%
= 100%

Original area = 4? r²,
New area = 4?(2r)² = 16 ? r²
Required increased % = [12?r²]/[4? r²] x 100 %= 300%

Original area = 6a²
New area = 6(2a)² = 24a²
Required increased % = (18a²/6a²) x 100%
= 300%

? 2?rh = 264
? 2 x (22/7) x r x 14 = 264
? r = 3
So, Volume = ?r²h
= (22/7) x 3 x 3 x 14 cm³
= 396 cm³

Radius of sphere = 9 cm
Volume of sphere = [ 4/3 x ? x (9)³] cm³ = 972? cm³
Radius of wire = 0.2 mm = 2/(10 x 10) cm = 1/50 cm
Let the length of wire be = L cm
Then, 972? = ? x (1/50)² x L
? L = (972 x 50 x 50 ) cm
?972? = ? x (1/50)² x L
? L = (972 x 50 x 50) cm
? Length of wire = (972 x 50 x 50)/100 m = 24, 300 m

Let their radii be 2r and 3r and height 5h and 3h respectively.
? Ratio of their volumes = [?(2r)² x 5h] / [?(3r)² x 3h]
= 20/27 = 20 : 27

Let their height be h and 2h radii be x and y respectively.
Then, ?x²h = ?y²(2h)
? x²/y² = 2/1
? x/y = ?2 / 1 = ?2 : 1

Let their radii be x and 2x .
Ratio of their surface areas = [4?x²]/[4?(2x)²] = 1/4 = 1 : 4

Curved surface area = ?rl
= (22/7 x 6 x 28) cm²
= 528 cm²

Number of bullets = Volume of cube / Volume of 1 bullet
= (22 x 22 x 22)/(4/3 x 22/7 x 1 x 1 x 1)
= 2541.