? (4/3) x (22/7) x r3 = (88/21) x (14)3
? r = 14
? Curved surface = 4 x (22/7) x 14 x 14 cm2 = 2464 cm2
4/3 ?r3 = 4?r2
? r = 3 units.
Number of cubes = (100 x 100 x 100)/(10 x 10 x 10) = 1000
Let depth = D cm.
Then, D x 6500 = 2.6 x 100 x 100 x 100
? D = (2.6 x 100 x 100 x 100) / 6500 cm
= 400 cm = 4 cm
Volume = Area x Thickness of rainfall
= 2 x 10000 x (5/100) m3
= 1000 m3
Thickness = Volume / Area
= (1/2)/10000 m
= (1 x 100)/(2 x 10000) cm
= 0.005 cm
Ratio of their volumes = [?r2h] / [(1/3)?r2h] = 3/1
= 3 : 1
Given, side of cube, a = 9
? Diagonal of cube = a?3 = 9?3
Required surface area = 4?r2
= 4 x ? x 42 = 664? sq cm
volume = (2/3)?r3
= (2/3) x ? x 33
= (2/3) x ? x 27
= 18? cm3
Total surface area of the pyramid
= [1/2(perimeter of the base) (Slant height) ] + Area of the base
= 1/2 (4) (4) (8) + 42 = 80 cm2
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