Longest rod = ?(10)2 + (10)2 + (10)2 cm
=?300 cm
=10?3 cm
2 | 1 | times |
2 |
2 | 3 | times |
4 |
∴ | (4x + 8) = | 5 | (x + 8) |
2 |
⟹ 8x + 16 = 5x + 40
⟹ 3x = 24
⟹ x = 8.
Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
(x + 16) | 24 |
According to question,
A shadow of length 40.25 meters is build for a height of 17.5 meters.
A shadow of length 1 meters is build for a height of 17.5 /40.25 meters.
A shadow of length 28.75 meters is build for a height of 17.5 x 28.75 /40.25 meters.
A shadow of length 28.75 meters is build for a height of 17.5 x 2875 /4025 meters.
A shadow of length 28.75 meters is build for a height of 17.5 x 575 /805 meters.
A shadow of length 28.75 meters is build for a height of 17.5 x 115/161 meters.
A shadow of length 28.75 meters is build for a height of 12.5 meters.
Here, P = 9 km/h, Q = 25 km/h, R = 30 km
x = 3 km/h, y = 5 km/h and z = 10 km/h
? Required average speed
= [P + Q + R] / [(P/x) + (Q/y) + (R/z)] = [9+25 + 30] / [(9/3) + (25/5) + (30/10)]
= 64/(3 + 5 + 3)
= 64/11
= 59/11 km/h
According to the question,
1st number = 3M, 2nd number = 4M
where, M = HCF
But given, M = 4
We know that,
LCM = Product of two numbers / HCF
= (3M x 4M) / M
LCM = 12M = 12 x 4 = 48
1/ (?3 + ?2)
= (?3 - ?2) / [ 1/ (?3 - ?2) x (?3 + ?2)]
= (?3 - ?2) / (3 - 2)
= (1.7732 - 1.414) = 0.318
Let the share of P = x
Then, Q's share = x + 30 and
R's share = (x + 30) + 60 = x + 90
Sum of money with P, Q and R = 300
? x + (x + 30) + (x + 90) = 300
? 3x + 120 = 300
? x = (300 - 120)/3 = 60
? Required ratio = 60 : (60 + 30) : (60 + 90) = 2 : 3 : 5
CP. = (80% of 90% of ?40000) + ?(1200)
= [(80/100) x (90/100) x 40000] + 1200
= (28800 + 1200)
= ?30000
? CP = ?30000
So, no gain no loss in the transaction.
Given, t = 8 yr, r = 3.5%, A = ? 364.80
Let amount = ? P
Since, A =P [1 + (RT/100)]
? 364.80 = P[1 + (3.5 x 8)/100]
? 364.80 = P[ 1+ (35 x 8)/100]
? 3648/10 = P x (128/100)
? P = 3648/128
= ? 285
Speed of tiger = 40 m/min
Speed of dear = 20 m/min
Relative speed = 40 - 20 = 20 m/min
Difference in distance = 50 x 8 = 400 m
? Time taken in overtaking (or catching) = 400/20 = 20min
? Distance travelled in 20 min = 20 x 40 = 800 m
Given, P = ? 8750., R = 7% T = 3 yr
According to the formula.
SI = (P x R x T)/100 = (8750 x 7 x 3)/100
= ? 1837.50
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