Volume of cylinder = ?r2= Area base x height
551 = 36.5 x h
h = 511/365 = 14 m
Maximum number of pieces that can be cut out
= (Volume of cake) / (Volume of Each piece of cake)
= (5 x 30 x 30)/(5 x 5 x 10) = 18
Since, the box is in the form of a cuboid.
? Required length = ?102 +82 + 52 cm
= ?189
= ?9 x 21
= 3?21 cm
Volume of new cube = [(5)3 + (4)3 + (3)3] cm3
= 216 cm3
Edge of this cube = ( 6 x 6 x 6)1/3 = 6 cm
Volume of new cube = (5)3 + (4)3 + (3)3 cm3
= 126 cm3
Edge of this cube = (6 x 6 x 6)1/3 = 6 cm
Let the edge of original cube = x cm
Edge of new cube = (2x) cm
Ratio of their volumes = x3 : (2x)3
= x3 : 8x3
= 1 :8
Thus the volumes be comes 8 times.
Length of longer rod = ?l2 + b2 + h2
= ?122 + 92 + 82
= ?144 + 81 + 64
= ?289
= 17 m
Longest rod = ?(10)2 + (10)2 + (10)2 cm
=?300 cm
=10?3 cm
Length of the rod = ?(20)2 + (16)2 + (12)2 m
= ?800 m
= 20?2 m
= (20 x 1.41) m
= 28.2 m
Thickness = Volume / Area
= (1/2)/10000 m
= (1 x 100)/(2 x 10000) cm
= 0.005 cm
Volume = Area x Thickness of rainfall
= 2 x 10000 x (5/100) m3
= 1000 m3
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