Volume of new cube = [(5)3 + (4)3 + (3)3] cm3
= 216 cm3
Edge of this cube = ( 6 x 6 x 6)1/3 = 6 cm
Volume of new cube = (5)3 + (4)3 + (3)3 cm3
= 126 cm3
Edge of this cube = (6 x 6 x 6)1/3 = 6 cm
Let the edge of original cube = x cm
Edge of new cube = (2x) cm
Ratio of their volumes = x3 : (2x)3
= x3 : 8x3
= 1 :8
Thus the volumes be comes 8 times.
Surface area = 6a2 = 726
? a2 = 121
? a = 11 cm
? Volume of the cube = (11 x 11 x 11) cm3
= 1331 cm3
? a3 = 512 = 8 x 8 x 8
? a = 8 cm
? Surface area = 6a2
=[6 x (8)2] cm2
=384 cm2
Let one diagonal be k.
Then, other diagonal = (60k/100) = 3k/5 cm
Area of rhombus =(1/2) x k x (3k/5) = (3/10)
= 3/10 (square of longer diagonal)
Hence, area of rhombus is 3/10 times.
Since, the box is in the form of a cuboid.
? Required length = ?102 +82 + 52 cm
= ?189
= ?9 x 21
= 3?21 cm
Maximum number of pieces that can be cut out
= (Volume of cake) / (Volume of Each piece of cake)
= (5 x 30 x 30)/(5 x 5 x 10) = 18
Volume of cylinder = ?r2= Area base x height
551 = 36.5 x h
h = 511/365 = 14 m
Length of longer rod = ?l2 + b2 + h2
= ?122 + 92 + 82
= ?144 + 81 + 64
= ?289
= 17 m
Longest rod = ?(10)2 + (10)2 + (10)2 cm
=?300 cm
=10?3 cm
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