Length of to the rope = Radius of circle
According to the question,
?r2 = 154
? r2 = 154 x (7/22) = 7 x 7 = 49
? r = ?49 = 7 m
Let original radius be r.
Then, according to the questions,
? (r + 1)2 - ?r2 = 22
? ? x [(r + 1)2 - r2] = 22
? (22/7) x (r + 1 + r ) x (r + 1 - r) = 22
? 2r + 1 = 7
? 2r = 6
? r = 6/2 = 3 cm
Increase in circumference of circle = 5%
? Increase in radius is also 5%.
Now, increase in area of circle = 2a + (a2/100) %
Where, a = increase in radius= 2 x 5 + (5 x 5)/100 % = 10.25%
Ratio of the areas of the circumcircle and incircle of a square
= [(Diagonal)2?] / [(Side)2?]
= [(Side x ?2)2] / (Side)2 = 2/1 or 2 : 1
Distance covered in 1 round
= (Total Distance) / (Total round)
= (1.76 x 1000)/350
= 176/35 m
? 2?r = (1.76 x 100) / 35 cm
2? = Diameter = 17600 x 7/22 x 35 = 160 cm
Given that, a = 6
According to the formula,
Percentage increase in area
= 2a + [a2/100]%
= 2 x 6 + [36/100]%
= (12 + 0.36)%
= 12.36%
The man takes 3600 s for 14.4 km
The man will take 88 s for
14.4 x (88/3600) = 352/1000 km = 352 m
Now, circumference of circular field = 352 m
? 2?r = 352 m
2 x (22/7) x r = 352
? r = 56 m
Therefore, area of the field = ?r2
= (22/7) x 56 x 56
= 8 x 22 x 56 m2
= 9856 sq m.
Let the radius of circular field = r m.
Speed of person in m/s = 30/60 = 1/2m/s
According to the question,
[(2?r) /(1/2)] - [(2r)/(1/2)] = 30
? 4?r - 4r = 30
? [4 x (22/7) - 4]r =30
? (125 - 4)r = 30
? (8.5)r = 30
? r = 30/8.5 = 3.5 m
Length ot rectangle = 40 m
Let breadth of = k
Then, according of the question,
(40 + k)15 = 40k
? 600 + 15k = 40k
? 25k = 600
? k = 24 m
Let the length of rectangle = L m
? Breadth of rectangle = B m
Using conditions from the question,
L - B = 23 ....(i)
2(L + B) = 206
L + B = 103 ....(ii)
On adding Eqs. (i) and (ii), we get
2L = 126
? L = 63 m
? B = 103 - 63 = 40 m
Then , area of rectangle = L x B
= 63 x 40
= 2520 m2 .
Let the width of the rectangle = k units
? Length = (2k + 5) units.
According to the question,
Area = k(2k + 5)
? 75 = 2k2 + 5k
? 2k2 + 5k - 75 = 0
? 2k2 + 15k - 10k - 75 = 0
? k(2k + 15) - 5(2k + 15) = 0
? (2k + 15) (k - 5) = 0
? k = 5 and -15/2
Width cannot be negative.
? Width = 5 units
? Length = 2x + 5 = 2 x 5 + 5 = 15 unit
? perimeter of the rectangle = 2(15 + 5)
= 40 units
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