Let the radius of the park be r, then
?r + 2r = 288
(? + 2)r = 288
? [(22/7) + 2]r = 288
? r = (288 x 7)/36 = 56
? Area of the park = (1/2)?r2
= (1/2) x (22/7) x 56 x 56
= 4928
Time taken by A to cover 100 meters
= 100 ÷ (5 * 5 / 18) = 72 seconds.
? B covers (100 - 8) or, 92 meters in (72 + 8) or, 80 seconds.
? Speed of B = ( 92 / 80 ) * ( 16 / 5 ) = 4.14 Km/h.
? Speed of the train = 72 km/hr = 72 x (5/18) = 20 m/sec.
Sum of the length of the train and tunnel = 540 + 160 = 700 metres.
? Required time taken to pass the tunnel = Time taken to cover 700 metres at 20 m/sec.
= 700/20
= 35 sec.
Area of the room =(544 x 374) cm2
size of largest square tile = H.C.F. of 544 & 374
= 34 cm
Area of 1 tile = (34 x 34) cm2
? Least number of tiles required
= (544 x 374) / (34 x 34) = 176
Speed in km/ hour =200
Speed in m/sec = 200 x 5/18 = 500/9 m/sec = 55.55 m/sec
The number '14' is the only EVEN number.
The average number of pens and pencils = 180
? Totol number of pens and pencils = 180 x 2 = 360
? Total number of pencils in the shop = 360 x (2/5) = 144
? 30% of 144 = (30/100) x 144 = 43.2 = 43
= 43 (approx)
According to the question,
Average age of man and his twin sons = 30
? Total age = 30 x 3 = 90 yr.
According to the question,
Ratio of father and one son = 5 : 2
? Ratio of father and both the sons = 5 : 2 : 2
(As sons are born on the same day.)
? 5k + 2k + 2k = 90 or 9k = 90
? k = 10
? Age of father = 5 x 10 = 50 yr.
(A + B)'s 1 day's work = | ❨ | 1 | + | 1 | ❩ | = | 1 | . |
15 | 10 | 6 |
Work done by A and B in 2 days = | ❨ | 1 | x 2 | ❩ | = | 1 | . |
6 | 3 |
Remaining work = | ❨ | 1 - | 1 | ❩ | = | 2 | . |
3 | 3 |
Now, | 1 | work is done by A in 1 day. |
15 |
∴ | 2 | work will be done by a in | ❨ | 15 x | 2 | ❩ | = 10 days. |
3 | 3 |
Hence, the total time taken = (10 + 2) = 12 days.
Sum of 11 numbers = 36 x 11 = 396
Sum of 9 numbers = 34 x 9 = 306
Sum of remaining two numbers =396 - 306 = 90
? The smaller number = (2 x 90)/(2 + 3) = 180/5 = 36
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