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  • Question
  • The perimeter of two squares are 68 cm. Find the perimeter of the third square whose area is equal to the different of the areas of these two squares.


  • Options
  • A. 64 cm
  • B. 60 cm
  • C. 32 cm
  • D. 8 cm

  • Correct Answer
  • 32 cm 

    Explanation

    a1 = 68/4 = 17 cm
    and a2 = 60/4 = 15 cm
    [ where a1 and a2 are sides]

    According to the question,
    Area of the third square = [(17)2 - (15)2 ]
    = (17 + 15) (17 - 15)
    = 32 x 2
    = 64 sq cm

    Let a3 = Side of the third square.

    According to the question, (a3)2 = 64 sq cm
    ? a3 = ?64 = 8 cm

    ? Perimeter of the third square = 4 x a3 = 4 x 8 = 32 cm.


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