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- Question
- The breadth of a rectangle is 25 m. The total cost of putting a grass bed on this field was ? 12375, at the rate of ? 15 per sq m. What is the length of the rectangular field?
Options- A. 27 m
- B. 30 m
- C. 33 m
- D. 32 m
- Correct Answer
- 33 m
ExplanationArea to the rectangular field = 12375/15 = 825 sq m
According to the question,
(L x B) = 825 [L = length and B = breadth]
? L x 25 = 825
? L = 825/25 = 33 m - 1. A rectangle has 20 cm as its length and 200 sq cm as its area. If the area is increased by 1 1/ 5 time the original area by increase its length only then the perimeter of the rectangle so formed (in cm) is
Options- A. 72
- B. 60
- C. 64
- D. 68 Discuss
- 2. Find the cost of carpeting a room 8 m long and 6 m broad with a carpet 75 cm wide at ? 20 per m.
Options- A. ? 1300
- B. ? 1500
- C. ? 1750
- D. ? 1280 Discuss
- 3. The length and perimeter of a rectangle are the ratio of 5 : 18 What well be the ratio of its length and breadth?
Options- A. 4 : 3
- B. 3 : 5
- C. 5 : 4
- D. 4 : 7 Discuss
- 4. Area of rectangular field is 3584 m 2 and the length and the breadth are in the ratio 7 : 2, respectively. What is the perimeter of the rectangle?
Options- A. 246 m
- B. 292 m
- C. 286 m
- D. 288 m Discuss
- 5. The perimeter of a rectangle having area equal to 144 cm 2 and sides in the ratio 4 : 9 is
Options- A. 52 cm
- B. 56 cm
- C. 60 cm
- D. 64 cm Discuss
- 6. What is the area of a square having perimeter 68 cm?
Options- A. 361 sq cm
- B. 284 sq cm
- C. 269 sq cm
- D. 289 sq cm Discuss
- 7. The perimeter of two squares are 68 cm. Find the perimeter of the third square whose area is equal to the different of the areas of these two squares.
Options- A. 64 cm
- B. 60 cm
- C. 32 cm
- D. 8 cm Discuss
- 8. A wheel make 4000 revolution in moving a distance of 44 km. Find the radius of the wheel.
Options- A. 15 m
- B. 27 m
- C. 25 m
- D. 28 m Discuss
- 9. If the area of a semi-circle be 77 sq m, find its perimeter.
Options- A. 36 m
- B. 42 m
- C. 48 m
- D. 54 m Discuss
- 10. A railing of 288 m is required for fencing a semi-circular park. Find the area of the park. (? = 22/7)
Options- A. 4928 m2
- B. 9865 m2
- C. 8956 m2
- D. 9856 m2 Discuss
Area problems
Search Results
Correct Answer: 68
Explanation:
l1 = 20 cm, A1 = 200 sq cm
? b1 = 200/20 = 10 cm
Now, A2 = 200 x 6/5 = 240 sq cm
b2 = 10 cm
? l2 = 240/10 = 24 cm
? Perimeter of new rectangle = 2(l2 + b2)
= 2(24 + 10) = 2 x 34 = 68 cm
Correct Answer: ? 1280
Explanation:
Area of the carpet = Area of the room
= 8 x 6 = 48 sq m
Width of the carpet = 75/100 = 3/4 m
Length of the carpet = 48 x (4/3)
= 16 x 4 = 64 m
? Cost of carpeting = 64 x 20 = ? 1280
Correct Answer: 5 : 4
Explanation:
According to the question,
l/[2(l + b)] = 5/18
? 10l + 10b = 18l = 10b
? l/b = 10/8 = 5/4
? l : b = 5 : 4
Hence, ratio of length and breadth of a rectangle is 5 : 4
Correct Answer: 288 m
Explanation:
Let length of the rectangular field = 7k m
and breadth of the rectangular field = 2k m
According to the question,
Area of a rectangular field = Length x Breadth
? 3584 = 7k x 2k
? 14 x k2 = 3584
? k2 = 3584/14 = 256
? k2 = 256 = 16 m
? Length of rectangular field = 7k = 7 x 16 = 112 m
And breadth of rectangular field = 2 x 16 = 32 m
? Perimeter of rectangle = 2(Length x Breadth)
= 2(112 + 32)
= 2 x 144
= 288 m
Correct Answer: 52 cm
Explanation:
Let l = 4k and b = 9k
Area of rectangle = l x b
144 = 4k x 9k
? k2 = 144/36
? k2 = 4
? k = 2
? l = 8 cm and b = 18 cm
Perimeter of rectangle = 2(l + b)
= 2(8 + 18)
= 2 x 26
= 52 cm
Correct Answer: 269 sq cm
Explanation:
According to the question,
4a = 68 [ where a = side]
?a = 68/4 = 17 cm
? Required area = a2
= (17)2 = 289 sq cm
Correct Answer: 32 cm
Explanation:
a1 = 68/4 = 17 cm
and a2 = 60/4 = 15 cm
[ where a1 and a2 are sides]
According to the question,
Area of the third square = [(17)2 - (15)2 ]
= (17 + 15) (17 - 15)
= 32 x 2
= 64 sq cm
Let a3 = Side of the third square.
According to the question, (a3)2 = 64 sq cm
? a3 = ?64 = 8 cm
? Perimeter of the third square = 4 x a3 = 4 x 8 = 32 cm.
Correct Answer:
Explanation:
Distance covered in 1 revolution
= (44 x 1000) / 4000
= 11 m
According to the question,
2?r = 11
? (44/7) x r = 11
? r = (11 x 7) / 44 = 1.75 m
Correct Answer: 36 m
Explanation:
According to the question,
Area of semi- circle = 77 m
(1/2) x ? x r2 = 77
? r2 = (77 x 2 x 7)/22
? r = 7m
?Circumference of semi- circle =?r + 2r
= ( ? + 2)r
= [(22/7) + 2] x 7
= 36 m
Correct Answer: 4928 m2
Explanation:
Let the radius of the park be r, then
?r + 2r = 288
(? + 2)r = 288
? [(22/7) + 2]r = 288
? r = (288 x 7)/36 = 56
? Area of the park = (1/2)?r2
= (1/2) x (22/7) x 56 x 56
= 4928
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