If the sides of a squares is increased by 25%, then the area of the squares will be increased by

Let the diagonals of the squares be 3x and 2x.
? Ratio of their areas = [(1/2) (3x²)] / [(1/2) (2x²)] = 9/4

Diagonal of square = ?2a [a = side]
4?2 = ?2 a
a = 4 cm
Now, area of square = a² = (4²) = 16
Side of a square whose area is 2 x 16.
a₁² = 32
? a₁ = ?32 ?a₁4?2

Now, diagonal of new square = ?2a
= ?2x 4 ?2
= 8 cm

According to the question,
area = ?3a²/4
= ?243 /4
? a² = ?81 x 3/?3
? a = ?9
= 3 cm

Given that, perimeter = 90 cm
? 3a = 90 cm       [a = side]
? a = 90/3 = 30 cm
? Area = ?3a² / 4 = ?3/4 x (30)²
= 900 x ?3/4 = 225?3 sq cm

Given ratio = 1/3 : 1/4 : 1/5 = 20 : 15 : 12
Let length of the sides be 20k, 15k and 12k.

Then, according to the question,
20k + 15k + 12k = 94
? 47k = 94
? k = 94/47 = 2

Smallest side = 12k = 12 x 2 = 24 cm

Ratio of area of 2 squares = (ratio of perimeter of 2 squares)²
= (24/12)²
= 4

Area of the field =1215/135 = 9 hec
= 90000 m² [1 hec =10000 m²]
? Side of the field = ?90000 = 300 m
Perimeter of the field = 4 x 300 = 1200 m

Now, cost of putting a fence around field = (1200 x 75)/100 = ? 900

Area of rhombus =(d₁ x d₂)/2
=(1 x 1.5)/2 m²
= 0.75 m²

Perimeter of rhombus
= 2 ? d₁ ² + d₂ ²
= 2 ?(4.8)² + (1.4)²
= 2 ?23.04 + 1.96
= 2 ?25
= 2 x 5 = 10 cm

Let First angle = 3k
Second angle = 4k
Third angle = 5k and
Fourth angle = 8k

We know 3k + 4k + 5k + 8k = 360°
? 20k = 360°
? k = 18 °

Measure of smallest angle = 3k
=3 x 18 °
= 54 °