Original area = ? x (r/2)2 = ?r2/4
Reduction in area = ? r2 - 3? r2/4
? Reduction per cent = [ 3?r2/4 x 4/(?r2) x 100 ] %
= 75%
Let the side of the square = y cm
Then, breadth of the rectangle = 3y/2 cm
? Area of rectangle = (40 x 3y/2) cm2
= 60y cm2
? 60y = 3y2
? y = 20
Hence, the side of the square = 20 cm
Let length = L and breadth = B
Let , New breadth = Z
Then, New length = ( 160 / 100) L.
= 8L / 5
? 8L / 5 x Z = LB
or Z = 5B/8
Decrease in breadth = (B-5B/8)
= 3B/8
? Decrease in percent = (3B/8 x1/B ) x 100 %
= 371/2%
Let the area of square be (9x)2 m2 and (x2) m2
Then, their sides are (3x) m and x metres respectively
? Ratio of their perimeters = 12x / 4x
=3:1
Area of the square field = 1 hectare
= 10000 m2
Side of the square = ? 10000 m = 100 m
Side of another square field = 100 + 1 = 101 m
? Required difference of area
= [(101)2 - (100)2] m2
=[(101 + 100 ) (101 - 100) ] m2
= 201 m2
Area of verandah = [(25 x 20) -(20 x 15)] m2
= 200 m2
? Cost of flooring = Rs. (200 x 3.50)
= Rs. 700
Original area = (22/7) x 9 x 9 cm2
New area = (22/7) x 7 x 7 cm2
? Decrease = 22/7 x [(9)2 -(7)2] cm2
=(22/7) x 16 x 2 cm2
Decrease percent = [(22/7 x 16 x 2) /( 7/22 x 9 x 9)] x 100 %
= 39.5 %
? 2?r - r = 37
? [(2 x 22/7) -1]r= 37
? 37r / 7= 37
? r = 7
So, area of the circle =(22/7) x 7 x 7 cm2
= 154 cm2
? 22/7 x r2 = 13.86 x 10000
? r2 = (13.86 x 10000 x 7) / 22
? r = 210 m
? Circumference = [2 x (22/7) x 210 ] m
= 1320 m
Cost of fencing = Rs. (1320 x 20)/100
= Rs . 264
? ( 22 x r2) / 7 = 38.5
? r2 =(38.5 x 7) /22
? r = 3.5 cm
? Circumference = 2 x (22/7) x 3.5 cm
= 22 cm
circumference = 2?r = 2 x (22 / 7) x r = 352
? r = (352 x 7) / (22 x 2) =56 cm
Now area = ?r2 = (22 / 7) x 56 x 56 m2
= 9856 m2
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.