Area of verandah = [(25 x 20) -(20 x 15)] m2
= 200 m2
? Cost of flooring = Rs. (200 x 3.50)
= Rs. 700
Let the side of the square = 100 m
So area of square = 100 x 100 = 10000.
New length = 140 m,
New breadth = 130 m
Increase in area = [(140 x 130) - (100 x 100)] m2
= 8200 m2
? Required increase percent = (8200/ 10000) x 100 % = 82%
Let the width of the room be x members
Then, its area = (4x) m2
Area of each new square room = (2x)m2
Let the side of each new room = y meters
Then, y2 = 2x
Clearly, 2x is a complete square when x=2
? y2 = 4
? y = 2 m .
Breadth of the rectangle = (150/15) cm
= 10 cm
New area = (4/3 x 150) cm2
= 200 cm2
New length = 200/10 cm
=20 cm
New perimeters = 2(20 + 10) cm
= 60 cm
Area of four walls = 2 x (l + b ) x h
? 2 x (7.5 + 3.5 ) x h = 77 m2
? h = 77 / (2 x 11) = 7/2
? h = 3.5 meters
Area of a four walls = 2(l + 8) x 6 = 168m2
? (l + 8) = 14
? l = 14-8
= 6 meters
Area of the square field = 1 hectare
= 10000 m2
Side of the square = ? 10000 m = 100 m
Side of another square field = 100 + 1 = 101 m
? Required difference of area
= [(101)2 - (100)2] m2
=[(101 + 100 ) (101 - 100) ] m2
= 201 m2
Let the area of square be (9x)2 m2 and (x2) m2
Then, their sides are (3x) m and x metres respectively
? Ratio of their perimeters = 12x / 4x
=3:1
Let length = L and breadth = B
Let , New breadth = Z
Then, New length = ( 160 / 100) L.
= 8L / 5
? 8L / 5 x Z = LB
or Z = 5B/8
Decrease in breadth = (B-5B/8)
= 3B/8
? Decrease in percent = (3B/8 x1/B ) x 100 %
= 371/2%
Let the side of the square = y cm
Then, breadth of the rectangle = 3y/2 cm
? Area of rectangle = (40 x 3y/2) cm2
= 60y cm2
? 60y = 3y2
? y = 20
Hence, the side of the square = 20 cm
Original area = ? x (r/2)2 = ?r2/4
Reduction in area = ? r2 - 3? r2/4
? Reduction per cent = [ 3?r2/4 x 4/(?r2) x 100 ] %
= 75%
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