The length of a rectangle room is 4 meters . if it can be partitioned into two equal square rooms . what is the length of each partition in meters?

Breadth of the rectangle = (150/15) cm
= 10 cm

New area = (4/3 x 150) cm²
= 200 cm²

New length = 200/10 cm
=20 cm

New perimeters = 2(20 + 10) cm
= 60 cm

Area of four walls = 2 x (l + b ) x h
? 2 x (7.5 + 3.5 ) x h = 77 m²
? h = 77 / (2 x 11) = 7/2
? h = 3.5 meters

Area of a four walls = 2(l + 8) x 6 = 168m²
? (l + 8) = 14
? l = 14-8
= 6 meters

Let the length, breadth and height of the room be l, b and h respectively

As per question
Cost of 2(l + b) x h = Rs. 48
? Required cost = cost of 2 (2l + 2b) x 2h
= cost of 4 [2(l + b) x h ]
= 4 x Rs. 48
= Rs. 192

Area of the plot = (3 x 1200) m²
= 3600 m²

Let breadth = y meters
Then Length = 4y meters,
Now area = 4y x y = 3600 m²
? y² = 900 m²
? y = 30 m

? Length of plot = 4y m
= (4 x 30) m
=120 m

Let the side of the square = 100 m
So area of square = 100 x 100 = 10000.
New length = 140 m,
New breadth = 130 m

Increase in area = [(140 x 130) - (100 x 100)] m²
= 8200 m²

? Required increase percent = (8200/ 10000) x 100 % = 82%

Area of verandah = [(25 x 20) -(20 x 15)] m²
= 200 m²
? Cost of flooring = Rs. (200 x 3.50)
= Rs. 700

Area of the square field = 1 hectare
= 10000 m²

Side of the square = ? 10000 m = 100 m
Side of another square field = 100 + 1 = 101 m

? Required difference of area
= [(101)² - (100)²] m²
=[(101 + 100 ) (101 - 100) ] m²
= 201 m²

Let the area of square be (9x)² m² and (x²) m²

Then, their sides are (3x) m and x metres respectively
? Ratio of their perimeters = 12x / 4x
=3:1

Let length = L and breadth = B
Let , New breadth = Z

Then, New length = ( 160 / 100) L.
= 8L / 5
? 8L / 5 x Z = LB
or Z = 5B/8

Decrease in breadth = (B-5B/8)
= 3B/8

? Decrease in percent = (3B/8 x1/B ) x 100 %
= 37¹/₂%