Let breadth = b meters.
then, length = 3b/2 meters
? b x 3b/2 = 2/3 X 10000
? b2 = (4 x 10000)/9
? b = ( 2 X 100)/3 m
? Length = (3/2) x (2/3) x 100 m
= 100 m
Area = 1440 / 160 hectares
= 9 hectares
= 90000 m2
? One side = ?90000 m
= 300 m
So perimeter = 4 x 300 m
= 1200 m
? Cost of fencing = Rs (1200 x 75) / 100
= Rs. 900
Let breadth = b meters.
Then, length = 4b/3 meters.
? b x 4b/3 = 300
? b2 = 300 x 3/4
? b2 = 225
? b = 15
Hence, required difference = [(Length) - (Breadth) ]
= 4b/3 - b
= b/3
= 15/3 m
= 5 m
Let base = b and altitude = h
Then, Area = b x h
But New base = 110b / 100 = 11b / 10
Let New altitude = H
Then,
Decrese = (h - 10h /11 )
= h / 11
? Required decrease per cent
= (h/11) x (1 / h ) x 100 %
= 91/11 %
Other side = ?5 2 - 42
= ? 9
=3 m
So The area of the rectangular field = 4 x 3
= 12 m2
Let Length = 5y meters and breadth = 3y meters.
Then, perimeter = 2 x (5y + 3y ) m = 16y meters ...(i)
But perimeter = Total Cost / Rate = 3000 / 7.50 m = 400 m ...(ii)
from eqs. (i) and (ii)
16y = 400
? y = 25
? Length - Breadth = (5 x 25 - 3 x 25 ) m
= 2 x 25 m
= 50 m
Let length of rectangular field = 5y,
so width = 4y.
From question
5y - 4y = 20m
? x = 20m
? Length = (5 x 20)m = 100 m
Breadth = (4 x 20) m = 80 m
? Perimeter = 2 (100 + 80 ) m = 360 m
Area of the square = (84 + 84) m2
Area of the rectangle = (144 x width) m2
From question both area would be same,
? Width = (84 x 84) / 144 m = 49 m
Area of the plot = (3 x 1200) m2
= 3600 m2
Let breadth = y meters
Then Length = 4y meters,
Now area = 4y x y = 3600 m2
? y2 = 900 m2
? y = 30 m
? Length of plot = 4y m
= (4 x 30) m
=120 m
Let the length, breadth and height of the room be l, b and h respectively
As per question
Cost of 2(l + b) x h = Rs. 48
? Required cost = cost of 2 (2l + 2b) x 2h
= cost of 4 [2(l + b) x h ]
= 4 x Rs. 48
= Rs. 192
Area of a four walls = 2(l + 8) x 6 = 168m2
? (l + 8) = 14
? l = 14-8
= 6 meters
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