If the base of a rectangular is increased by 10% and the area is unchanged , then the corresponding altitude must to be decreased by?

Other side = ?5 ² - 4²
= ? 9
=3 m

So The area of the rectangular field = 4 x 3
= 12 m²

Let Length = 5y meters and breadth = 3y meters.

Then, perimeter = 2 x (5y + 3y ) m = 16y meters ...(i)

But perimeter = Total Cost / Rate = 3000 / 7.50 m = 400 m ...(ii)

from eqs. (i) and (ii)
16y = 400
? y = 25

? Length - Breadth = (5 x 25 - 3 x 25 ) m
= 2 x 25 m
= 50 m

Required area = ?r² = ? x 25 x 25
= 625? sq m.

Radius = Diameter/2
? Diameter = 2 x Radius
= 2 x 3
= 6 cm

According to the formula,
? Percentage increase in sides = 10%
? Percentage increase diagonals = 10%

Let breadth = b meters.
Then, length = 4b/3 meters.
? b x 4b/3 = 300

? b² = 300 x 3/4
? b² = 225
? b = 15

Hence, required difference = [(Length) - (Breadth) ]
= 4b/3 - b
= b/3
= 15/3 m
= 5 m

Area = 1440 / 160 hectares
= 9 hectares
= 90000 m²

? One side = ?90000 m
= 300 m

So perimeter = 4 x 300 m
= 1200 m

? Cost of fencing = Rs (1200 x 75) / 100
= Rs. 900

Let breadth = b meters.
then, length = 3b/2 meters
? b x 3b/2 = 2/3 X 10000
? b² = (4 x 10000)/9
? b = ( 2 X 100)/3 m
? Length = (3/2) x (2/3) x 100 m
= 100 m

Let length of rectangular field = 5y,
so width = 4y.

From question
5y - 4y = 20m
? x = 20m
? Length = (5 x 20)m = 100 m
Breadth = (4 x 20) m = 80 m

? Perimeter = 2 (100 + 80 ) m = 360 m

Area of the square = (84 + 84) m²
Area of the rectangle = (144 x width) m²

From question both area would be same,
? Width = (84 x 84) / 144 m = 49 m