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- Question
- One side of a rectangular field is 4 meter and its diagonal is 5 meter. The area of the field is?
Options- A. 12 m2
- B. 15 m2
- C. 20 m 2
- D. 4?5 m2
- Correct Answer
- 12 m2
ExplanationOther side = ?5 2 - 42
= ? 9
=3 m
So The area of the rectangular field = 4 x 3
= 12 m2 - 1. What is the average of first 93 natural numbers?
Options- A. 45
- B. 46
- C. 47
- D. 49 Discuss
- 2. The cost of fencing a square field @ Rs. 20 per metre is Rs.10.080.How much will it cost to lay a three meter wide pavement along the fencing inside the field @ Rs. 50 per sq m
Options- A. 53800
- B. 43800
- C. 83800
- D. 73800 Discuss
- 3. What is the measure of an interior angle of a regular decagon?
Options- A. 120°
- B. 140°
- C. 144°
- D. 150° Discuss
- 4. The average weight of 100 students is 32 kg. The average weight of first 49 students is 30 kg and of last 50 students is 34 kg. What is the weight (in kg) of the 50th student?
Options- A. 25
- B. 30
- C. 32
- D. 33 Discuss
- 5. The average weight of Shubha, Govinda and Reshma is 65 kg. If the average weight of Shubha and Govinda be 63 kg and that of Govinda and Reshma be 70 kg, then the weight of Govinda is
Options- A. 41
- B. 71
- C. 88
- D. 46 Discuss
- 6. Which year has 366 days?
Options- A. 1900
- B. 1200
- C. 2500
- D. 1700 Discuss
- 7. A batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3. Find his average after 17th inning?
Options- A. 40
- B. 39
- C. 50
- D. 55 Discuss
- 8. A batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3. Find his average after 17th inning?
Options- A. 40
- B. 39
- C. 50
- D. 55 Discuss
- 9. In the given figure, PQRSTU is a regular hexagon of side 12 cm. What is the area (in sq.cm) of triangle SQU?
Options- A. 162√3
- B. 216√3
- C. 108√3
- D. 54√3 Discuss
- 10. In the given figure, four identical semicircles are drawn in a quadrant. XA = 7 cm. What is the area (in sq.cm) of shaded region?
Options- A. 70
- B. 140
- C. 77
- D. 84 Discuss
More questions
Correct Answer: 47
Correct Answer: 73800
Explanation:
perimeter = total cost / cost per m = 10080 /20 = 504m
side of the square = 504/4 = 126m
breadth of the pavement = 3m
side of inner square = 126 - 6 = 120m
area of the pavement = (126 x126) - (120 x 120) = 246 x 6 sq m
cost of pavement = 246*6*50 = Rs. 73800
Correct Answer: 144°
Correct Answer: 30
Correct Answer: 71
Correct Answer: 1200
Explanation:
NOTE: When a century year leaves a remiander 0, when divided by 400 then it is a leap year (366 days).
So, 1200 has 366 days.
Correct Answer: 39
Explanation:
Let the average after 17th innings = x
Then average after 16th innings = (x - 3)
Therefore 16 × (x - 3) + 87 = 17x
Therefore x = 39
Correct Answer: 39
Explanation:
Let the average after 17th innings = x
Then average after 16th innings = (x - 3)
Therefore 16 × (x - 3) + 87 = 17x
Therefore x = 39
Correct Answer: 108√3
Correct Answer: 84
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