The length and breadth of a rectangular piece of land are in the ratio of 5:3, the owner spent Rs.3000 for surrounding it from all the sides at Rs.7.50 per meter. The different between its length and breadth is?

Required area = ?r² = ? x 25 x 25
= 625? sq m.

Radius = Diameter/2
? Diameter = 2 x Radius
= 2 x 3
= 6 cm

According to the formula,
? Percentage increase in sides = 10%
? Percentage increase diagonals = 10%

According to the formula,
Percentage increase in diagonals = 5%

Required area = Length x Breadth
= 100 x 40 = 4000 sq m
= 4 x 10³ sq m

Other side = ?5 ² - 4²
= ? 9
=3 m

So The area of the rectangular field = 4 x 3
= 12 m²

Let base = b and altitude = h
Then, Area = b x h

But New base = 110b / 100 = 11b / 10

Let New altitude = H
Then,
Decrese = (h - 10h /11 )
= h / 11


? Required decrease per cent
= (h/11) x (1 / h ) x 100 %

= 9¹/₁₁ %

Let breadth = b meters.
Then, length = 4b/3 meters.
? b x 4b/3 = 300

? b² = 300 x 3/4
? b² = 225
? b = 15

Hence, required difference = [(Length) - (Breadth) ]
= 4b/3 - b
= b/3
= 15/3 m
= 5 m

Area = 1440 / 160 hectares
= 9 hectares
= 90000 m²

? One side = ?90000 m
= 300 m

So perimeter = 4 x 300 m
= 1200 m

? Cost of fencing = Rs (1200 x 75) / 100
= Rs. 900

Let breadth = b meters.
then, length = 3b/2 meters
? b x 3b/2 = 2/3 X 10000
? b² = (4 x 10000)/9
? b = ( 2 X 100)/3 m
? Length = (3/2) x (2/3) x 100 m
= 100 m