Let the diagonal of one square be (2d) cm
Then, diagonal of another square = d cm
? Area of first square = [ 1/2 x (2d)2] cm2
Area of second square = (1/2 x d2) cm2
? Ratio of area = (2d)2/ d2
= 4/1 = 4: 1
Length of the longest pole = ? [(10)2 + (8)2] m
= ? 164 m
= 12.8 m
Let breadth = b, length = 2b
? Area of rectangle = 2b x b
= 2b2
As per question.
? (2b - 5 ) (b + 5 ) = 2b2 + 75
? 5b = 75 + 25
? 5b = 100
? b = 100 / 5 = 20
Hence, length of the rectangle =2b
= 2 x 20
= 40 cm.
Area = 1/2 x (Diagonal)2
= (1/2) x 5.2 x 5.2 cm2
= 13.52 cm2
Perimeter = 2 x (36 + 21 ) m = 144 m
? Number of flagstaffs = 144 / 3 = 38
Let breadth = y meters,
Then, length = 2y meters
? Diagonal = ?y2 + (2y)2
= ?5y2 meters
So, ?5y2 = 9 ?5
? y= 9
Thus, breadth = 9 m and length = 18 m
? Perimeter = 2 (18 + 9) m = 54m.
Original area = ?(d/2)2
= (?d2) / 4
New area = ?(2d/2)2
= ?d2
Increase in area = (?d2 - ?d2/4)
= 3?d2/4
? Required increase percent
= [(3?d2)/4 x 4/(?d2) x 100]%
= 300%
Ratio of area = a2/ ?(3/4) a2
= 4/?3 = 4:?3
Area of equilateral triangle = ?3/4 a2 = 4?3.
? a2 = 16
? a = 4 cm
Req. Area = ?3/4 x a2 = ?3/4 x 82 cm2
= 16?3 cm2
Given that, a = 8 cm, b = 10 cm and c = 12 cm
We know, that
s = (a + b + c)/2
= (8 + 10 + 12)/2
= 30/2 = 15 cm
? (s - a) = (15 - 8) = 7 cm
(s - b) = (15 - 10) = 5 cm
(s - c) = (15 - 12) = 3 cm
? Area = ?s(s - a) (s - b) (s - c)
= ?15 x 7 x 5 x 3
= ?1575
= ?25 x 63
= 5?63 cm
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