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- Question
- The length and breadth of a playground are 36 m and 21 m respectively. Flagstaffs are required to be fixed on all along the boundary at a distance of 3 m apart. The number of flagstaffs will be?
Options- A. 37
- B. 38
- C. 39
- D. 40
- Correct Answer
- 38
ExplanationPerimeter = 2 x (36 + 21 ) m = 144 m
? Number of flagstaffs = 144 / 3 = 38 - 1. The simple interest on a sum of money will be Rs. 600 after 10 years. If the principal is trebled after 5 years the total interest at the end of 10 years will be?
Options- A. Rs. 600
- B. Rs. 900
- C. Rs. 1200
- D. Data inadequate Discuss
- 2. Simple interest on ? 1680 for 4 yr at 7 1/ 2 per annum is equal to the simple interest on ? 1200 at 7% per annum for a certain period of time. Time period of time is?
Options- A. 7 yr
- B. 6 yr
- C. 51/3 yr
- D. 71/4 yr Discuss
- 3. When a bank reduce the rate of interest from 6 1/ 2% per annum to 5 1/ 2% per annum, depositor withdrew Rs. 600 and thereby his interest reduced by ? 73. Find the initial deposit.?
Options- A. ? 4000
- B. ? 6000
- C. ? 7000
- D. ? 9000 Discuss
- 4. A man borrowed ? 12000 for 4 yr at 7 3/ 4 per annum and a year later he again borrowed another ? 12000 for 3 yr at the same rate. How much should he pay at the end to settle the loans?
Options- A. ? 30510
- B. ? 28610
- C. ? 31450
- D. ? 29590 Discuss
- 5. What will be the difference in the compound interest on ? 50000 at 12% for one year, when the interest is paid yearly and half- yearly?
Options- A. ?. 500
- B. ? 600
- C. ? 180
- D. ? 360 Discuss
- 6. Vikram borrowed ?. 6450 at 5% simple interest repayable in 4 equal instalments. What will be the annual instalment payable by him?
Options- A. ? 1710
- B. ? 1810
- C. ? 1910
- D. ? 1860 Discuss
- 7. At the rate of 8 1/ 2% per annum simple interest, a sum of ? 5800 will earn how much interest in 2 yr 3 months?
Options- A. ? 1300
- B. ? 1109
- C. ? 1509
- D. ? 1725 Discuss
- 8. In what time does a sum of money become four fold at the simple interest ratio of 10% per annum?
Options- A. 40 yr
- B. 30 yr
- C. 15 yr
- D. 25 yr Discuss
- 9. A sum was invested for 4 yr at a certain rate of simple interest. If it had been invested at 2% more annual rate of interest, then ? 56 more would have been obtained. What is the sum?
Options- A. ? 680
- B. ? 700
- C. ? 720
- D. ? 820 Discuss
- 10. A sum becomes 6 fold at 5% per annum. At what rate, the sum becomes 12 fold?
Options- A. 10%
- B. 12%
- C. 9%
- D. 11% Discuss
More questions
Correct Answer: Rs. 1200
Explanation:
Let the sum be Rs. P, SI = Rs. 600, Time = 10 years
? Rate (600 x 100) / (P x 10)%
S.I for first 5 years = Rs. (P x 5 x 6000)/(1000 x P) = Rs. 300
S.I for last 5 years = Rs. (3P x 5 x 6000)/(100 x P) = Rs. 900
Hence, total interest at the end of 10 years = 300 + 900 = Rs. 1200.
Correct Answer: 6 yr
Explanation:
Let the required period of time be T yr.
Then, (1680 x 4 x 15) /100 = (1200 x T x 7)/100
T = (1680 x 2 x 12)/(1200 x 7)
= 6 yr
Hence, the required time period is 6 yr.
Correct Answer: ? 4000
Explanation:
Initially ,
let P = ? A, R = 13/2% per annum and T = 1yr
SI = PRT/100 = (A x 1 x 13/2)/100 = ? 13A/200
Now, new deposit = ? (A - 600), R = 11/2 % per annum and T = 1yr
SI = PTR/100 = [(A - 600) x 1 x 11/2)/100] = ? 11(A - 600)/200
By the given condition ,
13A/200 - 11(A - 600)/200 = 73
? 13A - 11(A - 600 ) = 200 x 73
? 2A = 200 x 73 - 600 x 11
? 2A = 14600 - 6600
? 2A = 8000
? A = 4000
Hence, the initial investment is ? 4000.
Correct Answer: ? 30510
Explanation:
In the first case
P = Rs. 12000, T = 4 yr and R = 31/4 % per annum
SI = PTR/100 = (12000 x 4 x 31/4)/100 = ? 3720
A = (P + SI) = (12000 + 3720) = ? 15720
In the second case
P = ? 12000, T = 3 yr and R = 31/4 % per annum
SI = PTR/100 = (12000 x 3 x 31/4)/100 = ? 2790
A = (P + SI ) = (12000 + 2790) = ? 14790
? Total memory to be paid at the end = (15720 + 14790) = ? 30510
Correct Answer: ? 180
Explanation:
CI on ? 50000 at the rate of 12% for one year, when the interest is paid half-yearly
= 50000(1 + 6/100)2 - 50000
= [50000 x (53/50) x (53/50)] - 50000 = ? 6180
CI when the interest is paid yearly
= 50000(1 + 12/100)1 - 50000
= 50000(28/25 - 1) = 50000(3/25) = ? 6000
? Required difference = CI - SI = 6180 - 6000 = ? 180
Correct Answer: ? 1810
Explanation:
Let the annual instalment be Rs. P.
Amount of ? 100 after 4 yr = 100 + (100 x 5 x 4)/100 = ? 120
? Present Value (PV) of ? 120 due after 4 yr = ? 100
Present Value (PV) of ? due after 4 yr = 100P/120 = 5P/6
Similary, PV of ? P due after 3 yr = 20P/23
PV of ? P due after 2 yr = 10P/11
PV of ? P due after 1 yr = 20P/21
? 5P/6 + 20P/23 + 10P/11 + 20P/11 = 6450
? P = ? 1810
Correct Answer: ? 1109
Explanation:
Time = 2 yr 3 months = 21/4 yr = 9/4 yr
? SI = [5800 x (17/2) x (9/4)] / 100
= 8874/8
= ? 1109.25
= ? 1109
Correct Answer: 30 yr
Explanation:
Here, n = 4, R = 10, T = ?
According to the formula,
R = 100 (n - 1)/T
? 10 = [100(4 - 1)]/T = (100 x 3)/T
? T = 30 yr
Correct Answer: ? 700
Explanation:
According to the question
[P x (R + 2) x 4]/100 - [P x R x 4]/100 = 56
? (4PR + 8P - 4PR)/100 = 56
? 8P/100 = 56
? P = (56 x 100)/8 = ? 700
Correct Answer: 11%
Explanation:
SI at 5% = 6P - P = 5P
? 5P = (P x 5 x T) /100
? T = 100 yr
Now, for new rate (R),
11P = (P x R x 100)/100
? R =11%
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