Length of carpet = Total Cost / Rate
= 3600 / 30
= 120 m
Area of carpet = (120 x 75) / 100 m2
= 90 m2
? Area of the room = 90 m2
Breadth of the room = Area /Length
= 90 / 15 m
= 6m
Let length = l and breadth = b
Then, area = lb
New length = 2l
And new breadth = b/2
? New area = ( 2l ) x (b/2) = lb
So, there is no change in area .
Altitude = ?(13)2 - (5)2
= ?144 = 12m
? Area of the triangle = (5 x 12 ) / 2 m2
= 30m2
Area = 1/2 hectare = 10000 / 2 m2
= 5000 m2
Again Area = 1/2 x (Diagonal)2
So 1/2 x (Diagonal)2 = 5000m2
? Diagonal2= 10000
? Diagonal = 100
Given in the question,
n(M ? B) = 50, n(M) = 35, n(B) = 37, n(M ? B) =?
use the below formula
n(M ? B) = n(M) + n(B) ? n(M ? B)
We get 50 = 35 + 37 ? n(M ? B)
? n(M ? B) = 35 + 37 ? 50 = 72 ? 50 = 22
? 22 students have opted for both Mathematics and Biology.
Again number of students who have opted for only Mathematics = n(M) ? n(M ? B) = 35 ? 22 = 13.
n(A) = Biology students = 72%
n(B) = Mathematics students = 44%
Total students = n(A ? B) = 100%
? 100% = 72% + 44% - n(A ? B) = 116% - n(A ? B)
? n(A ? B) = 16%
? number of students studying both subjects = 40
? Let the total number of students be P
Now, according to the question,
16P/100 = 40
? P = 250
Let area 100 m2
Then, side = 10 m
New side = 125 % of 10
= (125/100) x 10
= 12.5 m
New area = 12.5 x 12.5 m2
=(12.5)2 sq. m
? Increase in area = (12.5)2 - (10)2 m2
= 22.5 x 2.5 m2
=56.25 m2
% Increase = 56.25 %
Let each side = x cm
Then, (x + 4 )2 - x2 = 60
? x 2 + 8x + 16 - x2 = 60
? x = 5.5 cm
Length = (40 x 10 ) dm = 400 dm.
Breadth = (15 x 10 ) dm = 150 dm.
Area of veranda = (400 x 150 ) dm2
Area of one stone = (6 x 5 ) dm2
? Required number of stones = (400 x 150) /(6 x 5) = 2000
Let breadth = y meters,
Then, length = 2y meters
? Diagonal = ?y2 + (2y)2
= ?5y2 meters
So, ?5y2 = 9 ?5
? y= 9
Thus, breadth = 9 m and length = 18 m
? Perimeter = 2 (18 + 9) m = 54m.
Perimeter = 2 x (36 + 21 ) m = 144 m
? Number of flagstaffs = 144 / 3 = 38
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