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- Question
- Vijay obtains a loan of 64000 against his fixed deposits. If the rate of interest be 2.5 paise per rupee per annum. Calculate the compound interest payable after 3 years?
Options- A. Rs. 4921
- B. Rs. 5020
- C. Rs. 4821
- D. Rs. 4920
- Correct Answer
- Rs. 4921
ExplanationP = Rs. 64000
r = 2.5 paise per rupee per annum (given)
= 0.025 rupee per rupee per annum
= 0.025 x 100 rupee per hundred rupee per annum
= 0.025 x 100 per cent per annum
= 2.5 per cent per annum
t = 3 years
C.I. = 6400[(1 + 2.5/100)3 - 1]
= 64000[(1.025)3 - 1]
= 64000[1.0769 - 1]
= 64000 x 0.0769
= 4921.6
= Rs. 4921
? The compound interest payable is Rs. 4921. - 1. The cash price of a refrigerator is Rs. 7044. A customer paid Rs. 2000 in case and promised to pay the remaining money in 3 yearly equal instalments at the rate of 5% per annum compound interest. What is the value of each instalment?
Options- A. Rs. 1865
- B. Rs. 1868.28
- C. Rs. 1752
- D. Rs. 1852.20 Discuss
- 2. The difference between the simple and the compound interest compounded every six months at the rate of 10 percent per annum at the end of two years is Rs. 124.05. What is the sum?
Options- A. Rs. 10000
- B. Rs. 6000
- C. Rs. 12000
- D. Rs. 8000 Discuss
- 3. A person invested a certain amount at simple interest at the rate of 6 percent annum earning Rs. 900 as an interest at the end of three years. Had the interest been compounded every year. How much more interest would he have earned on the same amount with the same interest after three years?
Options- A. Rs. 38.13
- B. Rs. 25.33
- C. Rs. 55.08
- D. Rs. 35.30 Discuss
- 4. If a sum of money placed at compound interest becomes 3 times of itself in 3 years. In how many years will it be 9 times at the same rate of interest?
Options- A. 6 years
- B. 9 years
- C. 12 years
- D. 5 years Discuss
- 5. Neeraj saves Rs. 400 at the end of each year and lends this saving at 5% p.a. compound interest, How much will it worth at the end of 3 years?
Options- A. Rs. 1312. 50
- B. Rs. 1284
- C. Rs. 1315
- D. Rs. 1324.05 Discuss
- 6. Divided Rs. 3903 between A and B, so that A's share at the end of 7 years may equal to B's share at the end of 9 years, compound interest being at 4 per cent?
Options- A. Rs. 2028, Rs. 1875
- B. Rs. 2018, Rs. 1885
- C. Rs. 2008, Rs. 1895
- D. Rs. 2038, Rs. 1865 Discuss
- 7. Akash borrows ? 65000 at 10% per annum simple interest for 3 yr and lends it at 10% per annum compound interest for 3 yr , Find his gain after three years.?
Options- A. ? 2015
- B. ? 1330
- C. ? 1300
- D. None of these Discuss
- 8. A father divided his property between his two sons A and B. A invests the amount at compound interest of 8% per annum and B invests the amount at 10% per annum simple interest. At the end of 2 yr, the interest received by B is ? 1336 more than the interest received by A. Find the share of A in the father's property of ? 25000.?
Options- A. ? 12000
- B. ? 13000
- C. ? 12500
- D. ? 10000 Discuss
- 9. What is the difference between the compound interest and simple interest calculated on an amount of ? 16200 at the end of 3 yr at 25% pa? (Rounded off to two digits after decimal)
Options- A. ? 3213.44
- B. ? 3302.42
- C. ? 3495.28
- D. ? 3290.63 Discuss
- 10. Divide ? 2602 between M and N, so that the amount of M after 7 yr is equal to the amount of N after 9 yr, the interest being compounded at 4% pa.
Options- A. ? 1352, ? 1250
- B. ? 1400, ? 1350
- C. ?1415, ?1300
- D. ?1500, ?1450 Discuss
Compound Interest problems
Search Results
Correct Answer: Rs. 1852.20
Explanation:
Remaining money = 7044 - 2000 = Rs. 5044
If each installment is of Rs. P
When the amount is Rs. P at the end of first, second and third year at the rate of 5% then principal will be - P/(1 + 5/100), P/(1 +5/100)2 and P/(1 +5/100)3
? P/(1 +5/100) + P/(1 + 5/100)2 + P/(1 +5/100)3 = 5044
? P(20/21) + P(20/21)2 + P(20/21)3 = 5044
? P(20/21) { 1 +(20/21) + (20/21)2} = 5044
? P(20/21) {1 +20/21 +400/441} = 5044
? P(20/21) {441 + 420 + 400/441} =5044
? P(20/21) (1261/441) =5044
? P = (5044 x 21 x 441)/ (20 x 1261) = Rs. 1852.20
Correct Answer: Rs. 8000
Explanation:
Let the sum be Rs. P, then
? [ P(1 +5/100)4 - P] - [(P x 10 x 2)/100 ] = 124.05
Solving the above equation,we get P = Rs. 8000.
Correct Answer: Rs. 55.08
Explanation:
Certain sum for the person = (900 x 100)/(6 x 3) =Rs. 5000
? Interest on Rs. 5000 by C.I. = 5000(1 +6/100)3 - 5000 = Rs. 955.08
? More interest =Rs. (955.08 - 900) = Rs. 55.08
Correct Answer: 6 years
Explanation:
Let the principle be P then amount be 3P
? 3P =P(1 + r/100)3
? 3 = (1 + r/100)3
On squaring on both the sides,
? (3)2 = {(1 + r/100)3}2
? 9 = (1 + r/100)6
Hence,it will become 9 times in 6 years.
Correct Answer: Rs. 1324.05
Explanation:
Amount after 3 years = 400(1 + 5/100)3 + 400(1 + 5/100)2 + 400(1 + 5/100)
= 400(1+ 5/100) {1+ 5/100)2 + (1 + 5/100) + 1 }
= 400(105/100) {(105/100)2 + (105/100) + 1}
= 400(21/20) {(21/20)2 + 21/20 + 1}
= 400(441/400 + 21/20 + 1)
= 400(441 + 420 + 400/400)
= 420(1261/400)
= Rs.1324.05
Correct Answer: Rs. 2028, Rs. 1875
Explanation:
We have (A's present share) (1 + 4/100)7 = (B's present share) (1 + 4/100)9
? A's present share/B's present share = (1 + 4/100)2 = (26/25)2 = 676/625
Dividing Rs. 3903 in the ratio of 676 : 625
? A's present share = 676/(676 + 625) of Rs .3903 = Rs. 2028
B's present share = Rs. 3903 - Rs. 2028 = Rs. 1875
Correct Answer: ? 2015
Explanation:
SI on ? 65000 at the rate of 10% for 3 yr
= (65000 x 10 x 3)/100 = ? 19500
CI on ? 65000 at the rate of 10% for 3 yr
= 65000(1 + 10/100)2 - 65000
= 65000(11 x 11 x 11 - 10 x 10 x 10)/1000 = ? 21515
? Required gain = 21515 - 19500 = ? 2015
Correct Answer: ? 10000
Explanation:
Suppose A gets ? P and B gets ? (25000 - P).
Interest received by A at the rate of 8% per annum CI
= P(1 + 8/100)2 - P
= P(27/25)2 - P
= 104P/625
Interest received by B at the rate of 10% per annum SI
= [(25000 - P) x 10 x 2]/100 = (25000 - P)/5
According to the question,
(25000 - P)/5 = 104P/(625 + 1336)
? P = 10000
Correct Answer: ? 3290.63
Explanation:
Let required difference be ? D.
By formula,
D = P x (R/100)2 x [(3 + R)/100]
= 16200 x (25/100)2 x [(3 + 25)/100]
= 16200 x 625/10000 x 13/4
= 162 x 625 x 13/4 x 100 = ? 3290.63
Correct Answer: ? 1352, ? 1250
Explanation:
Let the first part be ? M .
Then , second part = (2602 - M)
According to the question,
M(1 + 4/100)4 = (2602 - M) (1+4/100)9
? M/(2602 - M) = [(1 + 4/100)9]/[(1 + 4/100)7]
? M/(2602 - M) = (1 + 4/100)2 = (26/25) x (26/25) = 676/625
? 625M = 676 x 2602 - 676M
? 1301M = 676 x 2602
? M = (676 x 2602)/1301 = 676 x 2 = 1352
? The two parts are ? 1352 and ? (2602 - 1352) = ? 1250
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