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- Question
- The population of a country is 100 crore and it is the possibility that the population will become 13.31 crore in 3 yr. What will be the annual rate percent on this growth?
Options- A. 8%
- B. 12.7%
- C. 10%
- D. 15%
- Correct Answer
- 10%
ExplanationGiven, P = 10 crore
and population after 3 yr = 13.31 crore
According to the formula,
Population after n yr = P (1 + R/100 )n
? 13.31 = 10 (1 + R/100 )3
? 1331/1000 = (1 + R/100 )3
? (11/10)3 = (1 + R/100 )3
? 1 + R/100 = 11/10
? R/100 = 11/10 - 1 = 1/10
? R = 10% - 1. Find the compound interest for a sum of ? 9375 in 2 yr, if the rate of interest for the first year is 2% and for the second year is 4%.
Options- A. ? 570
- B. ? 670
- C. ? 770
- D. ? 760 Discuss
- 2. The principal amount which yields a compound interest of ? 208 in the second year at 4% is
Options- A. ? 5000
- B. ? 10000
- C. ? 130000
- D. ? 6500 Discuss
- 3. An amount at the rate of 5% pa becomes ? 10 more at compound interest than that of simple interest after 2 yr. Calculate the principal.
Options- A. ? 4000
- B. ? 4050
- C. ? 5000
- D. ? 5500 Discuss
- 4. The height of a tree increases every year 1/8 times. If the present height of the tree is 64 cm, then what will be its height after 2 yr?
Options- A. 76 cm
- B. 80 cm
- C. 81 cm
- D. 84 cm Discuss
- 5. The simple interest on a certain sum for 2 yr is ? 120 and compound interest is ? 129. Find the rate of interest.
Options- A. 14%
- B. 15%
- C. 12%
- D. none of the above Discuss
- 6. If the different between the compound interest and the simple interest on a certain sum for 2 yr at 8% per annum is ? 32, then the sum is
Options- A. ? 5000
- B. ? 5550
- C. ? 6000
- D. ? 5250 Discuss
- 7. What will be the principle, if the rate of 5% per annum can yield ? 410 as compound interest in 2 yr?
Options- A. ? 4000
- B. ? 42000
- C. ? 8000
- D. ? 21000 Discuss
- 8. At what per cent annual compound interest, rate, a certain sum amounts to its 27 times in 3 yr?
Options- A. 100%
- B. 150%
- C. 75%
- D. 200% Discuss
- 9. The compound interest on Rs. 30000 at 7% per annum for a
certain time is Rs. 4347. The time is?
Options- A. 2 years
- B. 21/2 years
- C. 3 years
- D. 4 years Discuss
- 10. The difference of compound interest on Rs.800 for 1 year at 20% per annum when compound half yearly and quarterly is?
Options- A. Nil
- B. Rs. 2.50
- C. Rs. 4.40
- D. Rs. 6.60 Discuss
Compound Interest problems
Search Results
Correct Answer: ? 570
Explanation:
Given, P = ? 9375, R1 = 2% and R2 = 4%
According to the formula,
A = P (1 + R1/100) (1 + R2/100)
= 9375 (1 + 2/100) (1 + 4/100)
= 9375 x (51/50) x (26/25)
= 7.5 x 51 x 26
= ? 9945
Now CI = A - P = 9945 - 9375 = ? 570
Correct Answer: ? 5000
Explanation:
Let the principal be ? P.
Amount after first year = (P x 104)/100 and
amount after second year P x (104/100) x (4/100)
According to the question.
(P x 104 x 4)/(100 x 100) = 208
? P = ? 5000
Correct Answer: ? 4000
Explanation:
Here, CI - SI = 10, R = 5%, n = 2 yr and P = ?
According to the formula,
CI - SI = PR2/1002
? 10 = (P x 25)/10000
? P = (400 x 10) = ? 4000
Correct Answer: 81 cm
Explanation:
Percentage growth = (1/8) x 100 % = 12.5%
Height after 2 yr = 64 x (1+ 12.5/100)2
= 64 x (9/8) x (9/8) = 81 cm
Correct Answer: 15%
Explanation:
Here, n = 2 yr, SI = ? 120 and CI = ? 129
CI = SI (1+ R/200)
? 129 = 120(1 + R/200)
? 129/120 = 1 + R/200
? (129/120) - 1 = R / 200
? 9/120 = R/200
? R = (9 x 200)/120 = 15%
Correct Answer: ? 5000
Explanation:
Given, R = 8%, D = ? 32 and P = ?
By formula, D = P(R/100)2
? 32 = P(8/100)2
? P = 32 x [(100 x 100)/(8 x 8)]
= ? 5000
Correct Answer: ? 4000
Explanation:
Let the amount be ? P
R = 5%, n = 2 yr and CI ? 410
By formula, CI = P [ (1 + R/100)n - 1 ]
? 410 = P [ (1 + 5/100)2 - 1]
? 410 = P [ (1 + 1/20)2 - 1]
? 410 = P [ (21/20)2 - 1]
? 410 = P [ 441/400 - 1 ]
? 410 = P [(441 - 400) /400] = P x 41/400
? P = (410 x 400)/41
? P = ? 4000
Correct Answer: 200%
Explanation:
Let sum = P
and given that n = 3 yr
According to the question,
Amount = 27 P
According to the formula,
Amount = P (1 + R/100)n
? 27 P = P (1 + R/100)3
? 27 = (1 + R/100)3
? (1 + R/100)3 = (3)3
? 1 + R/100 = 3
? R/100 = 3 - 1 = 2
? R = 200%
Correct Answer: 2 years
Explanation:
? 30000 x (1 +7/100)t = 30000 + 4347
? (107/100)t = 34347/30000
?11449/10000 = (107/100)2
? Time = 2 years
Correct Answer: Rs. 4.40
Explanation:
C.I. when reckoned half yearly
= Rs.[800 x (1 + 10/100)2 - 800]
= Rs. 168
C.I.when reckoned quarterly
= Rs.800[(1 + 5/100)4 - 1]
= 800[(194481 - 160000)/160000]
= 34481/200
= Rs.172.40
? Required difference =Rs.(172.40 - 168)
= Rs.4.40
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