Let the principal be ? P.
Amount after first year = (P x 104)/100 and
amount after second year P x (104/100) x (4/100)
According to the question.
(P x 104 x 4)/(100 x 100) = 208
? P = ? 5000
Here, CI - SI = 10, R = 5%, n = 2 yr and P = ?
According to the formula,
CI - SI = PR2/1002
? 10 = (P x 25)/10000
? P = (400 x 10) = ? 4000
Percentage growth = (1/8) x 100 % = 12.5%
Height after 2 yr = 64 x (1+ 12.5/100)2
= 64 x (9/8) x (9/8) = 81 cm
Here, n = 2 yr, SI = ? 120 and CI = ? 129
CI = SI (1+ R/200)
? 129 = 120(1 + R/200)
? 129/120 = 1 + R/200
? (129/120) - 1 = R / 200
? 9/120 = R/200
? R = (9 x 200)/120 = 15%
SI for on ? 12960 for 1 yr
= 13176 - 12960 = ? 216
By formula, SI = (P x R x T)/ 100
? 216 = (12960 x R x 1)/100
? R = 5/3 = 12/3
Here, D = ?6.40, R = 8% and n = 2 yr
Then, according to the formula,
Difference between compound interest and simple interest
D = PR2 / 1002
? 6.40 = P x 64/10000
? P = ? 1000
Given, P = ? 9375, R1 = 2% and R2 = 4%
According to the formula,
A = P (1 + R1/100) (1 + R2/100)
= 9375 (1 + 2/100) (1 + 4/100)
= 9375 x (51/50) x (26/25)
= 7.5 x 51 x 26
= ? 9945
Now CI = A - P = 9945 - 9375 = ? 570
Given, P = 10 crore
and population after 3 yr = 13.31 crore
According to the formula,
Population after n yr = P (1 + R/100 )n
? 13.31 = 10 (1 + R/100 )3
? 1331/1000 = (1 + R/100 )3
? (11/10)3 = (1 + R/100 )3
? 1 + R/100 = 11/10
? R/100 = 11/10 - 1 = 1/10
? R = 10%
Given, R = 8%, D = ? 32 and P = ?
By formula, D = P(R/100)2
? 32 = P(8/100)2
? P = 32 x [(100 x 100)/(8 x 8)]
= ? 5000
Let the amount be ? P
R = 5%, n = 2 yr and CI ? 410
By formula, CI = P [ (1 + R/100)n - 1 ]
? 410 = P [ (1 + 5/100)2 - 1]
? 410 = P [ (1 + 1/20)2 - 1]
? 410 = P [ (21/20)2 - 1]
? 410 = P [ 441/400 - 1 ]
? 410 = P [(441 - 400) /400] = P x 41/400
? P = (410 x 400)/41
? P = ? 4000
Let sum = P
and given that n = 3 yr
According to the question,
Amount = 27 P
According to the formula,
Amount = P (1 + R/100)n
? 27 P = P (1 + R/100)3
? 27 = (1 + R/100)3
? (1 + R/100)3 = (3)3
? 1 + R/100 = 3
? R/100 = 3 - 1 = 2
? R = 200%
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