Given, P = ? 50000, R = 12% and n = 3 Yr
According to the formula,
Amount = P (1 + R/100 )n
= 50000 (1 + 12/100 )3
= 50000 x (28/25) x (28/25) x (28/25)
= 16 x (28 x 28 x 28)/ 5 = 351232/5
= ? 70246.40
? CI = 702446.40 - 50000 = ? 20246.40
Interest on ? 1440 = ? 216 for the third year
? Rate percentage = (216 x 100)/(1440 x 1) = 15 %
2P = P (1 + R/100) 5
? 24 P = P(1 + R/100)20
? The amount becomes 24 times
= 16 times and required amount = 2400 x 16 = ? 38400
Let the rate be R% per annum.
Then,
1200 x (1 + R/100)2 = 1348.32
? (1 + R/100)2 =1348.32/1200 = 1.1236 = (1.06)2
? (1 + R/100) =1.06
? R/100 = 0.06
? R = 6%
The amount of Rs. 100 in one year at compound interest at 5% per annum payable half yearly.
= Rs. 100(1 + 5/2 /100)2
=Rs. 100(102.5/100)2
=Rs. 100(1.025)2
=Rs. 105.0625
Thus, the nominal rate of 5% payable half yearly has the same effect as the rate of 5.0625 per cent would have, if payable yearly.
Hence 5.0625 per cent is called the effective annual rate 5% per annum payable half yearly.
? P(1 + r/100)t = A
? 390625(1 + 4/100)t = 456976
? (1 + 4/100)t = 456976/390625 =(26/25)4
? (26/25)t = (26/25)4
? t = 4
? The required time is 4 years.
Using the formula, A = p ( 1 + R/100 )n
? 1352 = p(1 + 4/100 )2
? 1352 = p(1.04 )2
? p = 1352/(1.04)2 = ? 1250
Given R = 4 %, n = 2 yr and A = ? 169.
P = ?
Amount = P(1 + R/100)n
? 169 = P(1 + 4/100 )2
? 169 = P(26/25)2
? P = 169 x (25 x 25)/(26 x 26)
? P = 105625 / 676
= ? 156.25
Given, P = ? 31250,
n = 9 Month = 3 quarters and
R = 16% pa = 4% per quarter
According to the formula
Amount = P(1 + R/100 )n
= 31250(1 + 4/100 )3
= 31250 x (26/25) x (26/25) x (26/25)
= ? 35150
? CI = 35152 - 31250
= ? 3902
Let required amount be ? P.
According to the question,
2916 = P (1 + R/100)2 ... (i)
and 3149.28 = P(1 + R/100)3 ... (ii)
On dividing Eq. (ii) by Eq. (i), we get
1 + R/100 = 3149.28/2916
? R/100 = (3149.28/2916) - 1
? R = (233.28/2916) x 100 = 8%
From Eq. (i),
P = (2916 x 100 x 100)/(108 x 108)
= ? 2500
Let the sum be Rs. 100 then,
S.I.= Rs.(100 x 5 x 2)/100 =Rs.10
C.l.= Rs.[100 x (1 +5/100)2] =Rs.41/4
? difference between C.I. and S.I. = Rs. (41/4-10) = Re.0.25
? 0.25 : 1.50 : : 100 : P
? P = (1.50 x 100) / 0.25 = Rs. 600
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.