? Final Amount = Rs.[2800 x (1 + 10/100) x (1 +5/100)]
= Rs. [ 2800 x 11/10 x 21/20 ]
= Rs. 3234
? Required C.I. = Rs.(3234 - 2800) = Rs .434
Let time be t years
? 882 = 800( 1 +5/1000)t
? 882/800 = (21/20)t
? (21/20)2 = (21/20)t
? t =2
? Time = 2years
Let the sum be P.
Then, 1352 = P(1 +4/100)2
? 1352 = P x 26/25 x 26/25
? P = (1352 x 25 x 25) / (26 x 26) = 1250
? Principal = Rs. 1250
Let the principle is P
so compound interest = p x ( 1 + (12.5/100))sup>2 - p = 170
? p x (112.5/100) x (112.5/100) - p = 170
? P [ 12656.25 - 10000 ] = 170 x 10000
? p = (170 x 10000) / 2656.25
Simple interest SI = (P x T x R )/100
= [{(170 x 10000) / 2656.25} x 2 x 12.5] / 100
= 160
Let the sum be Rs . 100 then
S.I. = Rs.(100 x 5 x 2/100)= Rs. 10
C.I = Rs. [{100 x (1 + 5/100)2} - 100] = Rs. 41/4
? Difference between C.I and S.I = Rs. (41/4 - 10) = Re. 0.25
? 0.25 : 150 : : 100 : P
? P = (1.50 x 100) / 0.25 = Rs. 600
Here, A = ? 8800, T =2 yr, R = 5%
We know
SI = ART/(100 + RT) = (8800 x 5 x 2) / (100 + 5 x 2)
= (8800 x 10) / 110
= ? 800
Amount = Rs. 7500(1 + 4/100)2
= Rs. 7500 x 26/25 x 26/25
= Rs .8112
Let P be the principle and R% per annum be rate
Then, P(1 +R/100)3 = 3149.28 .....(i)
and P(1 + R/100)2 = 2916 .....(ii)
on dividing(i) and (ii) we get
? (1 + R/100) = 3149.28/2916
? R/100 = 233.28/2916
? R = 233.28/2916 x 100 = 8%
Now, P(1 + 8/100)2 = 2916
? P x 27/25 x 27/25 = 2916
? P = (2916 x 25 x 25)/(27 x 27)
= Rs. 2500
Let the principal be P and rate be r%.Then
2P = P(1 + r/100)5
? (1 + r/100)5 = 2
Let it be 8 times in t years, then
? 8P = P(1 + r/100)t
? (1 + r/100)t = 8
? (2)3 ? (1 + r/100)15
? t =15 year.
Let the principal be P. Then,
? P(1 +10/100)2 - P =420
? P(121 - 100/100) =420
? P = Rs. 2000
? Requared S.I.= Rs.(2000 x 2 x 10)/100
= Rs. 400
1600(1 +5/100)t = 1944.81
? (21/20)t =194481/160000 =(441/400)2 = (21/20)4
? T = 4( half years)
? Required time =2 years
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